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05 Oct 2020, 04:41
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
39% (02:59) correct
61%
(03:23)
wrong
based on 88
sessions
History
Date
Time
Result
Not Attempted Yet
The cost of digging a pit was $2694. How much will it cost approximately if the wages of workmen per day had been increased by 1/8 of the former wages and the length of the working day increased by 1/20 of the former period?
A. 2886
B. 2880
C. 2883
D. 2881
E. 2876
A. 2886
B. 2880
C. 2883
D. 2881
E. 2876
05 Oct 2020, 09:02
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The cost of digging a pit was $2694
New wage: 1 + \(\frac{1}{8}\) = \(\frac{9}{8 }\)of old wage
The new length of working hours: 1 + \(\frac{1}{20}\) = \(\frac{21}{20}\) of the old length of working hours.
Since the number of days is inversely proportional to working hours per day,
=> New number of days = \(\frac{20 }{ 21}\) * old number of days
Cost is directly proportional to wages per day
Cost is directly proportional to the number of days
New cost : 2,694 * \(\frac{9 }{ 8} * \frac{20 }{ 21}\) = 2886
Answer A
New wage: 1 + \(\frac{1}{8}\) = \(\frac{9}{8 }\)of old wage
The new length of working hours: 1 + \(\frac{1}{20}\) = \(\frac{21}{20}\) of the old length of working hours.
Since the number of days is inversely proportional to working hours per day,
=> New number of days = \(\frac{20 }{ 21}\) * old number of days
Cost is directly proportional to wages per day
Cost is directly proportional to the number of days
New cost : 2,694 * \(\frac{9 }{ 8} * \frac{20 }{ 21}\) = 2886
Answer A
05 Oct 2020, 10:31
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tanu11
\(2694 * \frac{9}{8}*\frac{20}{21} \) ~ \(2886\) , Answer must be (A)
