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17 Oct 2020, 13:41
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (00:58) correct
13%
(01:14)
wrong
based on 71
sessions
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On the xy-coordinate plane, points R(7,-3) and S(7,7) are the endpoints of the longest possible chord of a certain circle. What is the area of the circle?
(A) \(7\pi\)
(B) \(16\pi\)
(C) \(20\pi\)
(D) \(25\pi\)
(E) \(49\pi\)
(A) \(7\pi\)
(B) \(16\pi\)
(C) \(20\pi\)
(D) \(25\pi\)
(E) \(49\pi\)
17 Oct 2020, 14:28
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Bunuel
Hi Bunuel, could uou please check. The answer (Area) should be \(64\pi\)
The longest possible chord of the circle is the diameter of the circle
The distance between 2 points R \((x_1,y_1) and S (x_2,y_2)\) is given by \(RS = \sqrt{(x_2 – x_1)^2 + (y_2 – y_1)^2 }\)
Therefore \(RS = \sqrt{(7 – 7)^2 + (23 – 7)^2 } = \sqrt{16}^2 = 16\)
(This actually is not required in this case as the diameter lies on the stright line passing through x = 7. The length is the difference between the 2 y co ordinates = 23 - 7 = 16
The radius = 16 / 2 = 8
Area = \(r^2 * \pi = 8^2 \pi = 64 \pi\)
Arun Kumar
17 Oct 2020, 19:31
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I also got the answer 64pi.
