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Bunuel
A 60 liters mixture has milk and water in the ratio of 2 : 1. If the ratio is to be reversed, then what quantity of water should be added?

A. 20
B. 30
C. 40
D. 50
E. 60


60L of milk and water is in the ratio 2 : 1

Amount of Milk = \(\frac{2}{3} * 60 = 40L\) and amount of water = 60 - 40 = 20L

Let x liters of water be added to make the ratio of M : W = 1 : 2


Amount of Milk = 40 L (unchanged as we are adding only water)

Amount of Water = 20 + x


Then \(\frac{40}{20 + x} = \frac{1}{2}\)

80 = 20 + x

x = 60 L


Option E

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IMO E

The key thing to remember in Mixture questions is that >> in Most of the mixture questions, the volume of one of the elements would remain constant, though the initial ratio may change.

In the above question, the Volume of Milk would still be = 40 Litres ..(2/3 * 60)

When the ratio gets reversed just by adding water, this 40 litres of milk would represent 1/3 of Total volume (say X)

>>> 40 = 1/3 * X , therefor X = 120 (New Volume)

Water Added = 120 - 60 (Initial Volume) = 60 Litres
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Bunuel
A 60 liters mixture has milk and water in the ratio of 2 : 1. If the ratio is to be reversed, then what quantity of water should be added?

A. 20
B. 30
C. 40
D. 50
E. 60

Solution:


Currently, we see that we have 40 liters of milk and 20 liters of water. If we let w = the amount of water that should be added to reverse the milk-to-water ratio, we can create the equation:

(20 + w) / 40 = 2/1

20 + w = 80

w = 60

Answer: E
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Milk: Water =2:1 for 60liters. So, Milk = 40; Water=20
To make the ratio 1:2, keep milk = 40 constant. So you have to rise up water to 80.
So, water to be increased = 80-20 =60
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