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IanStewart could you please show how to do it with weighted average?

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Using alligation, you'd draw this number line:

---A-------60-----------------70----

and because the times are in a 4 to 6, or 2 to 3 ratio, the distances to the middle average are in a 2 to 3 ratio. Since the larger distance is 10, the smaller distance is thus 2/3 of that, or 20/3, and A = 60 - (20/3) = 53 1/3.

That's a weighted average solution using alligation -- if you solve weighted average problems algebraically, the solution would essentially be the one I posted above.
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Bunuel
The Ryder family traveled at an average rate of 60 miles per hour(mph), and it took 10 hours to complete their trip. If they trave1ed for 4 of their 10 hours at a constant speed of 70 mph, at what average speed did they trave1 for the remaining 6 hours to obtain the 60 mph average for the entire trip?

A. 53 1/3 mph
B. 53 2/3 mph
C. 54 1/3 mph
D. 55 1/3 mph
E. 55 2/3 mph

4*70+6*x=60*10
280+6x=600
6x=320
3x=160
x=53 1/3 A)
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