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01 Nov 2020, 00:15
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
70% (01:02) correct
30%
(01:14)
wrong
based on 107
sessions
History
Date
Time
Result
Not Attempted Yet
If m is a positive integer and n is an even prime number, which of the following can be the GCD of 20m and 6n?
A. 2
B. 4
C. 6
D. 10
E. 30
A. 2
B. 4
C. 6
D. 10
E. 30
Bunuel
n= can only be 2
so 6n= 12
All factors of 12 = 1*2*3*4*6*12 ( GCD of 6n and 20m has to be one among these )
if m is 1 then GCD= 4
If m =2 then GCD= 4
if m =3 then GCD= 12
Hence among the options the greatest value of GCD that is possible is 4
Ans- B
Hope it's clear.
01 Nov 2020, 05:05
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stne
Hi,
The GCF when m=3 will be 12.
60=2*2*3*5 and 12=2*2*3 so, 2^2*3=12.
Thus I think the answer has to be 4.
Thank you
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