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Difficulty:
25%
(medium)
Question Stats:
70% (01:01) correct
30%
(01:13)
wrong
based on 110
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If m is a positive integer and n is an even prime number, which of the following can be the GCD of 20m and 6n?
A. 2
B. 4
C. 6
D. 10
E. 30
_________________
A. 2
B. 4
C. 6
D. 10
E. 30
_________________
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Bunuel
n= can only be 2
so 6n= 12
All factors of 12 = 1*2*3*4*6*12 ( GCD of 6n and 20m has to be one among these )
if m is 1 then GCD= 4
If m =2 then GCD= 4
if m =3 then GCD= 12
Hence among the options the greatest value of GCD that is possible is 4
Ans- B
Hope it's clear.
_________________
- Stne
stne
Hi,
The GCF when m=3 will be 12.
60=2*2*3*5 and 12=2*2*3 so, 2^2*3=12.
Thus I think the answer has to be 4.
Thank you
Posted from my mobile device
Nups1324
Right , when m=3 then GCD is indeed 12 Goof up from my part. Thanks.
_________________
- Stne
GCD or GCF
Greatest common divisor or greatest common factor
Greatest common divisor or greatest common factor
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