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04 Nov 2020, 04:30
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Difficulty:
5%
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Question Stats:
87% (01:05) correct
13%
(01:28)
wrong
based on 75
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If a four-digit positive integer M183 is divisible by 11, what is the value of M ?
A. 5
B. 6
C. 7
D. 9
E. 8
A. 5
B. 6
C. 7
D. 9
E. 8
04 Nov 2020, 04:47
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Bunuel
The rule for divisiblity by 11 is -
Difference between sum of alternate digits is a multiple of 11 including 0.
M183 : M+8-(1+3)=M+4=11a
a cannot be 0 as M will become negative.
a cannot be >1, as M will become 2-digit.
So M+4=11....M=7
C
04 Nov 2020, 04:48
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M +8-1-3 = 11
M = 7
Since difference of sum of alternate digits should be zero or 11.
Posted from my mobile device
M = 7
Since difference of sum of alternate digits should be zero or 11.
Posted from my mobile device
