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05 Nov 2020, 01:15
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Difficulty:
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78% (00:55) correct
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In the figure, the square has two sides that are tangent to the circle. If the area of the circle is \(16x^2\pi\), what is the area of the square, in terms of x?
A. 16x^2
B. 25x^2
C. 32x^2
D. 64x^2
E. 128x^2
Attachment:
2020-10-27_12-56-27.png [ 9.22 KiB | Viewed 3316 times ]
05 Nov 2020, 02:09
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Explanation:
Area of circle = 16*x^2*π
πr^2 = 16*x^2*π
r^2 = 16*x^2
r = 4x
Dia = side of square = 2r = 8x
Area of square = (side)^2 = (8x)^2 = 64x^2
IMO-D
Area of circle = 16*x^2*π
πr^2 = 16*x^2*π
r^2 = 16*x^2
r = 4x
Dia = side of square = 2r = 8x
Area of square = (side)^2 = (8x)^2 = 64x^2
IMO-D
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05 Nov 2020, 04:14
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Side of the square = Diameter of the circle = 2*4x = 8x
Area of the square = 64x^2 D
Area of the square = 64x^2 D
