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11 Nov 2020, 04:04
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Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:06) correct
19%
(01:52)
wrong
based on 317
sessions
History
Date
Time
Result
Not Attempted Yet
If \(4^y = 8^{(y + 1)}\), what is the value of \(2^y\)?
(A) –8
(B) 1/8
(C) 1/3
(D) 1
(E) 8
(A) –8
(B) 1/8
(C) 1/3
(D) 1
(E) 8
11 Nov 2020, 06:53
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Bunuel
Given: \(4^y = 8^{(y + 1)}\)
Rewrite with equivalent basis: \((2^2)^y = (2^3)^{(y + 1)}\)
Apply the Power of a Power law to get: \(2^{2y} = 2^{3y + 3}\)
This means that: \(2y = 3y + 3\)
Solve to get: \(y = -3\)
So, \(2^y=2^{-3}=\frac{1}{2^3}=\frac{1}{8}\)
Answer: B
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11 Nov 2020, 08:00
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Bunuel
\(2^{2y} = 2^{3y + 3}\)
So, \(2y = 3y + 3\)
Or, \(y = 3\)
So, \(2^y = 8\) , Answer must be (E)
