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25 Nov 2020, 01:15
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
78% (01:09) correct
22%
(01:08)
wrong
based on 73
sessions
History
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Not Attempted Yet
A brick with dimensions 3, 4, and 9 has three holes bored completely through it as shown. Each hole has diameter 2. What is the net volume of the brick?
A. \(108 - 18\pi\)
B. \(108 - 15\pi\)
C. \(108 - 12\pi\)
D. \(108 - 9\pi\)
E. \(108 - 3\pi\)
Attachment:
2020-10-27_15-05-49.png [ 44.64 KiB | Viewed 2592 times ]
25 Nov 2020, 03:41
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Volume of entire brick without holes--> l*b*h = 9*3*4 = 108
Now the holes are cylindrical in shape. Hence volume of one hole --> π*r*r*h = π*1*1*3 = 3π
Volume of 3 holes = 3*3π = 9π
Volume of drilled brick = 108 - 9π
Hence IMO D is the answer
Posted from my mobile device
Now the holes are cylindrical in shape. Hence volume of one hole --> π*r*r*h = π*1*1*3 = 3π
Volume of 3 holes = 3*3π = 9π
Volume of drilled brick = 108 - 9π
Hence IMO D is the answer
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25 Nov 2020, 05:34
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Bunuel
pi.r^2.h=volcylinder=1^2.pi.3
abc=volume.rec.solid=3*4*9=108
recsolid-3cylinders=108-3(3pi)=108-9pi
(D)
