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Bunuel
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If y^(1) – 11 is negative, what is the greatest possible integer value Updated on: 15 Jan 2021, 21:46
Originally posted by Bunuel on 29 Dec 2020, 22:45.
Last edited by chetan2u on 15 Jan 2021, 21:46, edited 1 time in total.
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70% (00:41) correct 30% (01:27) wrong based on 116 sessions

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If \(y^2- 11\) is negative, what is the greatest possible integer value for y ?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
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C
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GMAT Focus 1: 735 Q90 V89 DI81
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If y^(1) – 11 is negative, what is the greatest possible integer value 30 Dec 2020, 10:01
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Bunuel
If \(\sqrt{y} – 11\) is negative, what is the greatest possible integer value for y ?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
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So, \(\sqrt{y} – 11<0.........\sqrt{y}<11..........y<121\).
Thus answer is 120.

But the options suggest that the question should be \(y^2 – 11\) is negative.
So, \(y^2 – 11<0.........y^2<11<16..........so \ \ -4<y<4\), as we are looking for integer values only.
Largest possible value = 3

OR the question could be \(y – \sqrt{11}\) is negative.
So, \(y – \sqrt{11}<0.........y<\sqrt{11}..........so \ \ y<4\), as we are looking for integer values only.
Largest possible value = 3

C
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If y^(1) – 11 is negative, what is the greatest possible integer value 31 Dec 2020, 08:07
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chetan2u
Bunuel
If \(\sqrt{y} – 11\) is negative, what is the greatest possible integer value for y ?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


So, \(\sqrt{y} – 11<0.........\sqrt{y}<11..........y<121\).
Thus answer is 120.

But the options suggest that the question should be \(y^2 – 11\) is negative.
So, \(y^2 – 11<0.........y^2<11<16..........so \ \ -4<y<4\), as we are looking for integer values only.
Largest possible value = 3

OR the question could be \(y – \sqrt{11}\) is negative.
So, \(y – \sqrt{11}<0.........y<\sqrt{11}..........so \ \ y<4\), as we are looking for integer values only.
Largest possible value = 3

C
Show more

I didn't understand. Whatever, If I think as \(\sqrt{y} – 11\) is negative, means if I deduct 11 from \(\sqrt{y}\) then the result will be negative and question y should be an integer. only \(\sqrt{4}\) gives an integer. So, the answer is D. I understand the as simple as I thought.

Hope you will make me clear.
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If y^(1) – 11 is negative, what is the greatest possible integer value 31 Dec 2020, 11:42
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chetan2u
Bunuel
If \(\sqrt{y} – 11\) is negative, what is the greatest possible integer value for y ?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


So, \(\sqrt{y} – 11<0.........\sqrt{y}<11..........y<121\).
Thus answer is 120.

But the options suggest that the question should be \(y^2 – 11\) is negative.
So, \(y^2 – 11<0.........y^2<11<16..........so \ \ -4<y<4\), as we are looking for integer values only.
Largest possible value = 3

OR the question could be \(y – \sqrt{11}\) is negative.
So, \(y – \sqrt{11}<0.........y<\sqrt{11}..........so \ \ y<4\), as we are looking for integer values only.
Largest possible value = 3

C

I didn't understand. Whatever, If I think as \(\sqrt{y} – 11\) is negative, means if I deduct 11 from \(\sqrt{y}\) then the result will be negative and question y should be an integer. only \(\sqrt{4}\) gives an integer. So, the answer is D. I understand the as simple as I thought.

Hope you will make me clear.
Show more

Hi

We are looking for the biggest possible integer, so we look for the biggest possible answer. Had it asked ‘ which of the following...?’, then we would have looked at the options.
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If y^(1) – 11 is negative, what is the greatest possible integer value 09 Jan 2021, 00:11
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This can be written as:
Root y - 11< 0
Root y < 11
; only 4 and 9 gives integer values for y to be less than 11.
Therefore only two int values possible: 2,3; greatest being 3

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If y^(1) – 11 is negative, what is the greatest possible integer value 15 Jan 2021, 21:11
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This question is confusing to me √y - 11 is negative, what is the greatest integer value of y. Well if I plug in 5, then that satisfies it, it seems. If we plug in 4, then the result is -9, but that's not the integer value of y.

Not really sure what this is even asking.

Bunuel?
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If y^(1) – 11 is negative, what is the greatest possible integer value 16 Jan 2021, 00:18
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Bunuel
If \(y^2- 11\) is negative, what is the greatest possible integer value for y ?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Show more



From the answer choices, I take a value and squared that value and subtract the value-form 11 to check whether the is negative.

A. 1-11>0 Out

B. 2^2-(4)-11<0; but this not the greatest value of the option.

C. 3^2(9)-11<0 the answer, because look that following

D. 4^2(16)-11>0 out

The answer is C
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