Bunuel
If \(\sqrt{y} – 11\) is negative, what is the greatest possible integer value for y ?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
So, \(\sqrt{y} – 11<0.........\sqrt{y}<11..........y<121\).
Thus answer is 120.
But the options suggest that the question should be \(y^2 – 11\) is negative.So, \(y^2 – 11<0.........y^2<11<16..........so \ \ -4<y<4\), as we are looking for integer values only.
Largest possible value = 3
OR the question could be \(y – \sqrt{11}\) is negative.So, \(y – \sqrt{11}<0.........y<\sqrt{11}..........so \ \ y<4\), as we are looking for integer values only.
Largest possible value = 3
C
I didn't understand. Whatever, If I think as \(\sqrt{y} – 11\) is negative, means if I deduct 11 from \(\sqrt{y}\) then the result will be negative and question y should be an integer. only \(\sqrt{4}\) gives an integer. So, the answer is D. I understand the as simple as I thought.
Hope you will make me clear.