Last visit was: 23 Apr 2026, 14:34 It is currently 23 Apr 2026, 14:34
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
810,855
Given Kudos: 105,853
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,855
If (vw^2)(xy)^2z^4 = 10, which of the following CANNOT be negative? 30 Dec 2020, 04:30
Kudos
Add Kudos
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

5% (low)

Question Stats:

96% (00:36) correct 4% (00:43) wrong based on 51 sessions

History

Date
Time
Result
Not Attempted Yet
If \((vw^2)(xy)^2z^4 = 10\), which of the following CANNOT be negative?

(A) v
(B) w
(C) x
(D) y
(E) z
ShowHide Answer
Official Answer
A
User avatar
imeanup
User avatar
Joined: 15 Jun 2017
Last visit: 24 Mar 2026
Posts: 452
Own Kudos:
635
Given Kudos: 8
Location: India
Posts: 452
Kudos: 635
If (vw^2)(xy)^2z^4 = 10, which of the following CANNOT be negative? 30 Dec 2020, 04:36
Kudos
Add Kudos
Bookmarks
Bookmark this Post
\((vw^2)(xy)^2z^4 = 10\)
\(vw^2x^2y^2z^4=10\)
If \(v\) is \(-ve\), then the complete equation becomes negative.

Ans A
avatar
aritrar4
avatar
Current Student
Joined: 12 Jun 2020
Last visit: 06 Sep 2024
Posts: 103
Own Kudos:
98
Given Kudos: 147
Location: India
Schools: S.P.Jain Institute (A) IIMA PGPX'23 (A) IIMC MBAEx'23 (A) ISB '23 (I) IIMB EPGP'23 (D)
GMAT 1: 680 Q47 V35
GMAT 2: 690 Q49 V34
GMAT 3: 710 Q50 V35
GPA: 3.73
Products:
My Reviews
Schools: S.P.Jain Institute (A) IIMA PGPX'23 (A) IIMC MBAEx'23 (A) ISB '23 (I) IIMB EPGP'23 (D)
GMAT 3: 710 Q50 V35
Posts: 103
Kudos: 98
If (vw^2)(xy)^2z^4 = 10, which of the following CANNOT be negative? 30 Dec 2020, 04:37
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Everything else has even powers except V. Since even powers are always positive, V has to be positive here since the product is a positive value.

Posted from my mobile device
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
20,872
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,872
If (vw^2)(xy)^2z^4 = 10, which of the following CANNOT be negative? 30 Dec 2020, 05:46
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given

    • An expression.


To Find

    • Which of the term cannot be negative.


Approach and Working Out


    • The expression can be rewritten as,
      o v × \(w^2\)× \(x^2\) × \(y^2\)× \(z^4\) = 10
      o Here, all terms in \(w^2\), \(x^2\), \(y^2\), \(z^4 \)are positive.
      o This means v must also be positive.

Correct Answer: Option A
Moderators:
Bunuel
Math Expert
109785 posts
Krunaal
Tuck School Moderator
853 posts