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29 Jan 2021, 09:30
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Difficulty:
5%
(low)
Question Stats:
88% (01:35) correct
12%
(02:15)
wrong
based on 137
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A policeman, who is 80 m away from a thief, starts chasing him. The thief is running at a speed of 10 m/s. After exactly 8 seconds, the distance between them is 40m. What is the policeman’s speed?
(a) 10.5 m/s
(c) 12 m/s
(c) 15 m/s
(b) 17 m/s
(c) 25 m/s
(a) 10.5 m/s
(c) 12 m/s
(c) 15 m/s
(b) 17 m/s
(c) 25 m/s
29 Jan 2021, 09:51
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There are 2 ways we can go about solving this
(1) By the concept of Relative Speed, when 2 objects are moving in the same direction, the net effect is the difference between the speeds.
Let the policeman's speed = x m/s.
Then Time = Distance / Relative Speed
8 = 40 / (x - 10)
8x - 80 = 40
8x = 120
x = 15 m/s
(2) In 8 seconds the thief has run 8 * 10 = 80 m. Therefore the total distance run by the thief = 80 + 80 = 160 m
Let the speed of the policeman = x m/s. The distance covered by the policeman = 8x
After 8 seconds the policeman is 40 m behind the thief, which means the distance covered by the policeman = 160 - 40 = 120m
8x = 120
x = 15 m/s
Option C
Arun Kumar
(1) By the concept of Relative Speed, when 2 objects are moving in the same direction, the net effect is the difference between the speeds.
Let the policeman's speed = x m/s.
Then Time = Distance / Relative Speed
8 = 40 / (x - 10)
8x - 80 = 40
8x = 120
x = 15 m/s
(2) In 8 seconds the thief has run 8 * 10 = 80 m. Therefore the total distance run by the thief = 80 + 80 = 160 m
Let the speed of the policeman = x m/s. The distance covered by the policeman = 8x
After 8 seconds the policeman is 40 m behind the thief, which means the distance covered by the policeman = 160 - 40 = 120m
8x = 120
x = 15 m/s
Option C
Arun Kumar
29 Jan 2021, 10:32
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In 8 seconds the distance between the thief and the policeman reduced by 40 meters, or 5 meters per second. So the speed of police is 5 m/s higher than that of the thief - 15 m/s. C)
