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Hoozan
In a certain physic class, the ratio of the number of physics majors to non-physics majors is 3 to 5. If two of the physics majors were to change their major to biology, the ratio would be 1 to 2. How many physics majors are in the class?
(A) 16
(B) 18
(C) 24
(D) 30
(E) 32
Set the number of physics majors as \(x\). Then there are \(\frac{5}{3}x\) non-physics majors. The new ratio give us:
\(\frac{x-2}{\frac{5}{3}x} = \frac{1}{2}\)
\(x - 2 = \frac{5}{6}x\)
\(\frac{1}{6}x = 2\)
\(x = 12\) would be the number of physics majors.
Hoozan maybe something is up with your question?
Number of Physics majors = 3x
Number of Non-physics majors = 5x (where x is a common ratio multiplier)
Now, if 2 physics majors were to shift to major in biology (Non-physics major) our current number of physics major would reduce by 2 while non-physics would increase by 2
\(\frac{3x - 2}{5x + 2}\) = \(\frac{1}{2}\)
upon solving we get x = 6
So current physics major = 3x = 18 (B)
You mentioned that there are \(\frac{5}{3}x\) non-physics majors. So when 2 shift to biology shouldn't this ratio change to \(\frac{5}{3}\)\(+ 2\)