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Bunuel
Let m denote the number of ways in which 4 different books are distributed among 10 persons, each receiving none or one only and let n denote the number of ways of distribution if the books are all alike. Then:

(A) m = 4n
(B) n = 4m
(C) m = 24n
(D) m = 32n
(E) m = 36n

Are You Up For the Challenge: 700 Level Questions: 700 Level Questions

The first part is a permutation question, because the books are all different.

\(m=\frac{10!}{6!}=7*8*9*10\)

Second part is a combinations question because the books are all the same.

\(n=10C4=\frac{7*8*9*10}{4*3*2}=3*7*10\)

m and n differ by a factor of 24, because that is what we divided n by: \(4*3*2=24\). The numerator of n was originally identical to m.

Thus, answer is C.
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