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26 Feb 2021, 09:30
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
65% (00:49) correct
35%
(01:09)
wrong
based on 52
sessions
History
Date
Time
Result
Not Attempted Yet
An urn contains 7 red and 4 blue balls. Two balls are drawn with replacement. What is the probability that the balls are both red ?
A. 49/121
B. 21/55
C. 41/121
D. 27/55
E. 65/121
A. 49/121
B. 21/55
C. 41/121
D. 27/55
E. 65/121
26 Feb 2021, 09:42
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Bunuel
Pls check
The answer should be 7/11 * 7/11 = 49/121
Not in answer choices.
Posted from my mobile device
Pls check
The answer should be 7/11 * 7/11 = 49/121
Not in answer choices.
Posted from my mobile device
rvgmat12
Joined: 19 Oct 2014
Last visit: 27 Mar 2026
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Schools: Wharton '23 Booth '23 INSEAD Jan'21 Intake
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26 Feb 2021, 09:44
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Probability of drawing two red balls is 7/11*6/10 if without replacement Answer is B
Posted from my mobile device
Posted from my mobile device
