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09 Mar 2021, 08:45
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
94% (01:36) correct
6%
(00:57)
wrong
based on 33
sessions
History
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Time
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Not Attempted Yet
The ages of two persons differ by 30 years. If 10 years ago, the elder one was 4 times as old as the younger one, what are their present ages ?
(A) 50 yrs, 20 yrs
(B) 45 yrs, 15 yrs
(C) 40 yrs, 10 yrs
(D) 35 yrs, 5 yrs
(E) 34 yrs, 4 yrs
(A) 50 yrs, 20 yrs
(B) 45 yrs, 15 yrs
(C) 40 yrs, 10 yrs
(D) 35 yrs, 5 yrs
(E) 34 yrs, 4 yrs
09 Mar 2021, 09:00
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Bunuel
Equation 1: A - B = 30
Equation 2: A-10 = 4(B-10)
You could either look at the options and eliminate choices or solve for A and B to get 50yrs and 20yrs ---- OPTION A
09 Mar 2021, 09:00
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In this question, if we look at the answer choices, we simply need to reduce the two ages the answer choices by 10 and then check if the larger number is 4 times the smaller number.
Option A will become 40 years and 10 years
Option B will become 35 years and 5 years
Option C, D, and E is not possible (they don't uphold the second condition).
Only option A holds.
Therefore, A is the correct answer.
Option A will become 40 years and 10 years
Option B will become 35 years and 5 years
Option C, D, and E is not possible (they don't uphold the second condition).
Only option A holds.
Therefore, A is the correct answer.
