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12 Mar 2021, 03:15
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
72% (01:02) correct
28%
(01:29)
wrong
based on 109
sessions
History
Date
Time
Result
Not Attempted Yet
How many three-digit numbers can be formed without using the digits 2, 3, 5, 7 if the repetition of the digits is allowed?
(A) 216
(B) 180
(C) 162
(D) 156
(E) 125
(A) 216
(B) 180
(C) 162
(D) 156
(E) 125
14 Mar 2021, 20:20
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Bunuel
Restrictions
1) Digits to be used: 0, 1, 4, 6, 8, 9
2) No repetition allowed
Let the number be xyz
Now x can take any value except 0, so 5 ways
y can take any values including 0, but excluding the digit used for x. So 5 ways
z can take remaining 4 values.
Total ways: 5*5*4=100 ways.
The answer is not in choices.
May be the question meant repetitions allowed.
Then x can take 5 values, and both y and z can take 6 values each.
Total: 5*6*6=180
B, but the question should be ‘repetition is allowed.’
