Given that $p = 0.5(p-30) and we need to find the value of p, if $($($p))=-30Let's solve the problem using two Methods
Method 1: SubstitutionLet's take each answer choice and check which one satisfies
A. –70$($($p))=-30
=> $($($-70))=-30
To find $-70 we need to compare what is after $ in $-70 and $p
=> We need to substitute p with -70 in $p = 0.5(p-30) to get the value of $-70
=> $-70 = 0.5(-70-30) = 0.5*-100 = -50
=> $($($p))= $($-50)
Similarly, $-50 = 0.5(-50-30) = 0.5*-80 = -40
=> $($($p))= $-40 = 0.5(-40-30) = 0.5*-70 = -35 ≠ -30 =>
FALSEB. –50=> $($($-50))=-30
=> $($($-50)) = $($-40) = $-35 = 0.5(-35-30) = 0.5*-65 = -32.5 ≠ -30 =>
FALSEC. –30=> $($($-30))=-30
=> $($($-30)) = $($(0.5(-30-30))) = $($(0.5*-60)) = $($-30) = $-30 = -30 =>
TRUEIn Test Situation we don't need to solve further but I am solving to complete the solution
D. 10=> $($($10))=-30
=> $($($10)) = $($(0.5(10-30))) = $($(0.5*-20)) = $($-10) = $((0.5(-10-30))) = $(0.5*-40) = $(-20) = 0.5(-20-30) = 0.5*-50 = -25 ≠ -30 =>
FALSEE. 30=> $($($30)) = $($(0.5(30-30))) = $($(0.5*0)) = $($0) = $((0.5(0-30))) = $(0.5*-30) = $(-15) = 0.5(-15-30) = 0.5*-45 = -22.5 ≠ -30 =>
FALSESo,
Answer will be CMethod 2: Algebra$($($p)) = $($(0.5(p-30)))
To find $(0.5(p-30)) we need to compare what is after $ in $(0.5(p-30)) and $p
=> We need to substitute p with 0.5(p-30) in $p = 0.5(p-30) to get the value of $(0.5(p-30))
=> $(0.5(p-30)) = 0.5(0.5(p-30)-30) = 0.5(0.5*p - 0.5*30 - 30) = 0.5(0.5*p - 15 - 30) = 0.5(0.5*p - 45)
=> $($($p)) = $($(0.5(p-30))) = $(0.5(0.5*p - 45))
Similarly, $(0.5(0.5*p - 45)) = 0.5(0.5(0.5*p - 45) - 30) = 0.5(0.5*0.5*p - 0.5*45 - 30) = 0.5(0.25*p - 22.5 - 30) = 0.5(0.25*p - 52.5)
=> $($($p)) = 0.5(0.25*p - 52.5) = -30 (given)
=> Multiplying both sides by 8 we get
8*0.5(0.25*p - 52.5) = 8*-30 = -240
=> 4 * 0.25p - 4*52.5 = -240
=> p - 210 = -240
=> p = -240 + 210 = -30
So,
Answer will be CHope it helps!
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