Last visit was: 11 Dec 2024, 19:11 It is currently 11 Dec 2024, 19:11
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 11 Dec 2024
Posts: 97,815
Own Kudos:
685,159
 [4]
Given Kudos: 88,242
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,815
Kudos: 685,159
 [4]
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
User avatar
EuropaGust
Joined: 06 Mar 2021
Last visit: 17 May 2023
Posts: 34
Own Kudos:
Given Kudos: 111
GMAT 1: 720 Q50 V37
GPA: 4
Products:
GMAT 1: 720 Q50 V37
Posts: 34
Kudos: 15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 11 Dec 2024
Posts: 19,854
Own Kudos:
24,260
 [2]
Given Kudos: 288
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 19,854
Kudos: 24,260
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
minminlulu
Joined: 16 May 2022
Last visit: 18 May 2022
Posts: 1
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi all,

Please could you explain this further. Is $ a specific mathematical function (like √)? I've never come across this before. I'm particularly confused by these parts of the above solution. For example, where is the -80 coming from in the first line?

$($p) = $(-50) = 0.5(-80) = -40, and $($($p))) = $(-40) = 0.5(-70) = -35
$($p) = $(-40) = 0.5(-70) = -35, and $($($p))) = $(-35) = 0.5(-65) = -32.5

I don't understand why you can't do the following:

p = -30
$p = 0.5(p-30)
$ x -30 = 0.5(-30-30)
$ x -30 = 0.5(-60)
$ x -30 = -30
$ = 1

Therefore, p = -30 because if you plug $ = 1 and p = -30 into the above, you get the following:

$p = 0.5(p-30)
1 x -30 = 0.5(-30-30)
-30 = 0.5(-60)
-30 = -30

Any advice would be appreciated.
User avatar
BrushMyQuant
Joined: 05 Apr 2011
Last visit: 09 Dec 2024
Posts: 2,044
Own Kudos:
Given Kudos: 100
Status:Tutor - BrushMyQuant
Location: India
Concentration: Finance, Marketing
Schools: XLRI (A)
GMAT 1: 700 Q51 V31
GPA: 3
WE:Information Technology (Computer Software)
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Schools: XLRI (A)
GMAT 1: 700 Q51 V31
Posts: 2,044
Kudos: 2,297
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given that $p = 0.5(p-30) and we need to find the value of p, if $($($p))=-30

Let's solve the problem using two Methods

Method 1: Substitution

Let's take each answer choice and check which one satisfies

A. –70
$($($p))=-30
=> $($($-70))=-30

To find $-70 we need to compare what is after $ in $-70 and $p
=> We need to substitute p with -70 in $p = 0.5(p-30) to get the value of $-70

=> $-70 = 0.5(-70-30) = 0.5*-100 = -50
=> $($($p))= $($-50)
Similarly, $-50 = 0.5(-50-30) = 0.5*-80 = -40
=> $($($p))= $-40 = 0.5(-40-30) = 0.5*-70 = -35 ≠ -30 => FALSE

B. –50
=> $($($-50))=-30
=> $($($-50)) = $($-40) = $-35 = 0.5(-35-30) = 0.5*-65 = -32.5 ≠ -30 => FALSE

C. –30
=> $($($-30))=-30
=> $($($-30)) = $($(0.5(-30-30))) = $($(0.5*-60)) = $($-30) = $-30 = -30 => TRUE
In Test Situation we don't need to solve further but I am solving to complete the solution

D. 10
=> $($($10))=-30
=> $($($10)) = $($(0.5(10-30))) = $($(0.5*-20)) = $($-10) = $((0.5(-10-30))) = $(0.5*-40) = $(-20) = 0.5(-20-30) = 0.5*-50 = -25 ≠ -30 => FALSE

E. 30
=> $($($30)) = $($(0.5(30-30))) = $($(0.5*0)) = $($0) = $((0.5(0-30))) = $(0.5*-30) = $(-15) = 0.5(-15-30) = 0.5*-45 = -22.5 ≠ -30 => FALSE

So, Answer will be C

Method 2: Algebra

$($($p)) = $($(0.5(p-30)))

To find $(0.5(p-30)) we need to compare what is after $ in $(0.5(p-30)) and $p

=> We need to substitute p with 0.5(p-30) in $p = 0.5(p-30) to get the value of $(0.5(p-30))
=> $(0.5(p-30)) = 0.5(0.5(p-30)-30) = 0.5(0.5*p - 0.5*30 - 30) = 0.5(0.5*p - 15 - 30) = 0.5(0.5*p - 45)

=> $($($p)) = $($(0.5(p-30))) = $(0.5(0.5*p - 45))

Similarly, $(0.5(0.5*p - 45)) = 0.5(0.5(0.5*p - 45) - 30) = 0.5(0.5*0.5*p - 0.5*45 - 30) = 0.5(0.25*p - 22.5 - 30) = 0.5(0.25*p - 52.5)

=> $($($p)) = 0.5(0.25*p - 52.5) = -30 (given)
=> Multiplying both sides by 8 we get
8*0.5(0.25*p - 52.5) = 8*-30 = -240
=> 4 * 0.25p - 4*52.5 = -240
=> p - 210 = -240
=> p = -240 + 210 = -30

So, Answer will be C
Hope it helps!

Watch the following video to learn the Basics of Functions and Custom Characters

Moderator:
Math Expert
97815 posts