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15 Apr 2021, 08:45
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (02:11) correct
16%
(02:21)
wrong
based on 73
sessions
History
Date
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Not Attempted Yet
Lathe machine A manufactures metal parts thrice as fast as lathe machine B. Lathe machine B manufactures 300 X-type bearings in 60 days. If each machine manufactures bearings at a constant rate, how many Y-type bearings does lathe machine A manufacturer in 10 days, if each Y-type bearing takes 2.5 times of the time taken to manufacturer each X-type bearing?
(A) 40
(B) 50
(C) 54
(D) 60
(E) 64
(A) 40
(B) 50
(C) 54
(D) 60
(E) 64
15 Apr 2021, 09:09
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Bunuel
Machine A has three times the rate of machine B, so it produces 900 X-type bearings in 60 days.
Y-type bearings take 2.5 times the amount of time, therefore Machine A produces 900 Y-type bearings in \(60*2.5 = 150\) days.
Finally divide by 15 to get the amount in 10 days, which is \(900/15 = 60\).
Ans: D
15 Apr 2021, 10:21
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Bunuel
Machine B makes 5 X-Type bearings in 1 day => 300/60
It takes 2.5 times of X-Type to make a Y-Type bearing
So, Machine B will make only 2 bearings in 1 day => 2.5*y=5, y=2
Machine A's rate is thrice that of Machine B.
So, Machine A can make 6 Y-Type bearings in a day
Hence, Machine A can make 60 Y-Type bearings in 10 days.
Imp thing to note: Rate is constant.
Answer: D
