Last visit was: 26 Apr 2026, 05:30 It is currently 26 Apr 2026, 05:30
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Apr 2026
Posts: 109,836
Own Kudos:
811,350
 [2]
Given Kudos: 105,893
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,836
Kudos: 811,350
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
avatar
GCMEMBER
Joined: 09 Dec 2019
Last visit: 03 Jun 2021
Posts: 123
Own Kudos:
Given Kudos: 5
Posts: 123
Kudos: 176
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
praveen27sinha
Joined: 13 Mar 2016
Last visit: 06 Mar 2022
Posts: 41
Own Kudos:
Given Kudos: 89
Location: India
Concentration: General Management, Entrepreneurship
WE:General Management (Energy)
Products:
Posts: 41
Kudos: 98
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
TarunKumar1234
Joined: 14 Jul 2020
Last visit: 28 Feb 2024
Posts: 1,102
Own Kudos:
Given Kudos: 351
Location: India
Posts: 1,102
Kudos: 1,357
Kudos
Add Kudos
Bookmarks
Bookmark this Post
What is the greatest possible straight line distance, in inches, between any two points on a rectangular box that is 5 inches wide, 3 inches long, and 4 inches high?

For the greatest distance, one side length= \(\sqrt{3^2 + 4^2}\) = 5 and another side = 5

So, the distance = \(\sqrt{5^2 + 5^2}\) = 5\(\sqrt{2}\)

I think C. :)
User avatar
sumitkrocks
Joined: 02 Jul 2017
Last visit: 22 Aug 2023
Posts: 637
Own Kudos:
Given Kudos: 333
Location: India
Concentration: Strategy, Technology
GMAT 1: 730 Q50 V39
GMAT 2: 710 Q50 V36
Products:
GMAT 2: 710 Q50 V36
Posts: 637
Kudos: 879
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Shortest distance will be distance between two diagonally opposite edges = \(\sqrt{3^2+4^2+5^2} \)=5\(\sqrt{2}\)

C is the answer
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,887
Kudos
Add Kudos
Bookmarks
Bookmark this Post

Solution


Given:
    • A rectangular box having a width of 5 inches, length of 3 inches, and a height of 4 inches.

To find:
The greatest possible straight line distance between the two points lying on the box.

Approach and Working:
The greatest distance between two points in a cuboid = length of the body diagonal of the cube.
    • The length of the body diagonal = √(l2 + b2 + h2), where l = length, b = breadth, h = height.
    • Thus, the greatest distance = √(52 + 32 + 42) = √50 = 5√2 inches.

Hence the correct answer is Option C.

Answer: C
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 26 Apr 2026
Posts: 22,286
Own Kudos:
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,286
Kudos: 26,537
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
What is the greatest possible straight line distance, in inches, between any two points on a rectangular box that is 5 inches wide, 3 inches long, and 4 inches high?

A. 2√5
B. 5
C. 5√2
D. 10
E. 50


Solution:

The greatest possible straight line distance, in inches, between any two points on a rectangular box that is 5 inches wide, 3 inches long, and 4 inches high is the length of the space diagonal of the box, which has a length of √(5^2 + 3^2 + 4^2) = √50 = 5√2.

Answer: C
Moderators:
Math Expert
109836 posts
Tuck School Moderator
852 posts