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21 Apr 2021, 06:15
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
87% (01:24) correct
13%
(01:19)
wrong
based on 76
sessions
History
Date
Time
Result
Not Attempted Yet
What will be the sum of all odd numbers between 30 and 50?
(A) 625
(B) 500
(C) 400
(D) 225
(E) 150
(A) 625
(B) 500
(C) 400
(D) 225
(E) 150
29 Apr 2021, 05:08
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Bunuel
So the first term will be \(31\) and the last term will be \(49\)
Also there will be a total of \(10\) terms.
We can use the formulae for " Sum of n terms of an A.P "
\(\frac{10}{2}(31 + 49 )= 400 \)
Ans-C
Hope it's clear.
29 Apr 2021, 05:50
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Solution:
In such questions, figure out the end points.
31 is the first odd number after 30 and 49 the last before 50.
So number of odd numbers = 49-31 / 2 +1
(We add 1 to include 31 and 49 both in the count. We divide by 2 because odd numbers occur as every second number after the first ,31,33,35..and so on)
=10 terms
Its now an AP of 10 terms(n=10) and first term being 31(a) and last term 49(l)
Sum = n/2(a +l)
= 10/2 (31+49)
=5 x 80
=400 (option c)
Devmitra Sen
GMAT SME
In such questions, figure out the end points.
31 is the first odd number after 30 and 49 the last before 50.
So number of odd numbers = 49-31 / 2 +1
(We add 1 to include 31 and 49 both in the count. We divide by 2 because odd numbers occur as every second number after the first ,31,33,35..and so on)
=10 terms
Its now an AP of 10 terms(n=10) and first term being 31(a) and last term 49(l)
Sum = n/2(a +l)
= 10/2 (31+49)
=5 x 80
=400 (option c)
Devmitra Sen
GMAT SME
