Bunuel
Papayaya, a popular soft drink, contains only four ingredients. Soda water comprise 4/7 of Papayaya and natural lemon juice makes 1/3 of Papayaya. The amounts of sugar and papaya puree in Papayaya are equal. Due to a malfunction, the mixing machine mixes double the regular amount of lemon juice and three times the regular amount of papaya puree. If no other changes were made to the relative quantities of the ingredients, what is the fractional portion of soda water in the drink that comes out of the malfunctioning machine?
A. 7/30
B. 7/21
C. 2/5
D. 12/29
E. 4/7
Given that Papayaya contains:
\(\frac{4}{7}=\frac{12}{21}\) of soda water;
\(\frac{1}{3}=\frac{7}{21}\) of lemon juice;
\(\frac{1}{21}\) of sugar: \(\frac{1-(\frac{12}{21}+\frac{7}{21})}{2}\);
\(\frac{1}{21}\) of papaya puree: \(\frac{1-(\frac{12}{21}+\frac{7}{21})}{2}\).
So, out of total of 21 units we need 12 units of soda water, 7 units of lemon juice, 1 unit of sugar and 1 unit of papaya puree.
Due to a malfunction, the mixing machine used 7*2=14 units of lemon juice (instead of 7) and 1*3=3 units of papaya puree (instead of 1).
Hence, the fraction of soda water in the final mixture is \(\frac{12}{12+14+3+1}=\frac{12}{30}=\frac{2}{5}\).
Answer: C.
Similar question to practice:
https://gmatclub.com/forum/miguel-is-mix ... 09740.htmlHope it helps.