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Let the red quota be 100 and the blue quota be 120. Half the daily quota for both is 110.
This means that every hour red makes 10 pills and blue makes 12.

Blue starts at 8:00 and works for 2.75 hours until 10:45.
2.75*12 = 33

Pills left to be produced: 110-33 = 77

Working together blue and red make 22 pills an hour.

77/22 = 3 11/22 or 3.5 hours

10:45 + 3.5 hours = 14:15

Answer B
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let red balls be 10x, then blue balls=12x
the blue machine started at 8 and worked for 2.75hour producing 1.2x*11/4hrs = 3.3x balls
so now we have to produce 1/2(total balls produced)=1/2*22x=11x

we have already prodcued 3.3x till 10:45, now we need to produce 11x-3.3x=7.7x
after 10.45,both machines worked simultaneously to produce 1x+1.2x=2.2x per hour
so 7.7/2.2=3.5hours

hence 10:45+3.5=2:15
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In the "Mashburn" pharmaceutical company there are two machines - a machine that produces blue pills and a machine that produces red pills. The machines are operated 10 hours a day, and the daily quota of the "blue" machine is 20% greater than that of the red machine.

If the "blue" machine was switched on at 8:00 and the "red" machine at 10:45, at what time will half of the combined daily quota be manufactured?

Let the daily quota for Red machine be x red pills per day
Daily quota for Blue machines = 1.2x blue pills per day

Combines daily quota = x + 1.2x = 2.2x pills per day
Half of combined daily quota = 1.1x pills per day

Let the time be t when half of the combined daily quota be manufactured

(t-8)1.2x/10 + (t-10.75)x/10 = 1.1x
1.2t - 9.6 + t - 10.75 = 11
2.2t = 11 + 9.6 + 10.75 = 31.35
t = 31.35/2.2 = 14.25 = 14:15 hrs

IMO B
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