Without any algebra, you can notice that the Areas given are Integer results and all the answer choices for the Rectangle’s Area are also integer results. It is therefore likely that the dimensions of each given line segment length is an Integer.
Area of triangle ADY = area of triangle DXC = 4
(1/2) L W = 4
L * W = 8
Since the other triangle, BXY, has a different integer area of 9, it seems likely that the rectangle is not a square and adjacent sides AD and DC are different Positive Integer lengths.
2 positive integers that multiple to a product or 8 are:
4 * 2 = 8 ————— and ———— 1 * 8 = 8
Case 1: let AD = 8 and DC = 4
To keep the area of the 2 right triangles DAY and DCX at 4 ——-> this would mean AY = 1 and XC = 2
Because it is a rectangle and the opposite sides are equal:
AY + YB = DC ——-> 1 + YB = 4 ———> YB = 3
And
CX + XB = AD ———-> 2 + XB = 8———> XB = 6
Area of right triangle BXY would be = (1/2) (YB) (XB) = (1/2) (3) (6) = 9
Area of triangle AYD = (1/2) (DA) (AY) = (1/2) (8) (1) = 4
And area of triangle DCX = (1/2) (DC) (CX) = (1/2) (4) (2) = 4
All the Triangle Area constraints are satisfied and the rectangle’s dimensions are given by:
DC = AB = 4 ——— and ———— AD = BC = 8
****(in fact, if you switched the dimensions around, you would still come up with a valid rectangle that satisfies the triangle area constraints with DC = AB = 8 and AD = BC = 4......since we are only concerned with the Area of the rectangle and not which side is the length and which side is the width, you still end up with the Same Answer)****
Area of Rectangle = (4) (8) = 32
32
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