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Updated on: 06 Jun 2021, 06:12
Originally posted by AlexTheTrainer on 06 Jun 2021, 06:09.
Last edited by Bunuel on 06 Jun 2021, 06:12, edited 1 time in total.
Last edited by Bunuel on 06 Jun 2021, 06:12, edited 1 time in total.
Renamed the topic.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
77% (02:44) correct
23%
(02:51)
wrong
based on 148
sessions
History
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Time
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Not Attempted Yet
Due to a malfunctioning Heisenberg compensator in the transporter, Adriella was stranded in an Ardanian mine shaft. At 12:00, she uses her Type 1 phaser to cut through the zenite ore to open air, which will take 7 hours. At 12:30, Desmina, situated directly on the other side of the mineshaft, uses her Type 2 phaser to cut through the ore directly towards Adriella. If Desmina’s Type 2 phaser would have taken 6 hours to reach Adriella’s original location, what time did the two of them meet?
(A) 1:30
(B) 3:00
(C) 3:30
(D) 4:30
(E) 5:00
Posted from my mobile device
(A) 1:30
(B) 3:00
(C) 3:30
(D) 4:30
(E) 5:00
Posted from my mobile device
06 Jun 2021, 08:55
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Given: Due to a malfunctioning Heisenberg compensator in the transporter, Adriella was stranded in an Ardanian mine shaft. At 12:00, she uses her Type 1 phaser to cut through the zenite ore to open air, which will take 7 hours. At 12:30, Desmina, situated directly on the other side of the mineshaft, uses her Type 2 phaser to cut through the ore directly towards Adriella.
Asked: If Desmina’s Type 2 phaser would have taken 6 hours to reach Adriella’s original location, what time did the two of them meet?
Work done by Adriella till 12:30 = .5/7 = 1/14
Work left = 1 - 1/14 = 13/14
Work done by Adriella and Desmina in 1 hour = 1/6 + 1/7 = 13/42
Time taken by both to complete the work = 42/13 * 13/14 = 42/14 = 3 hours
The two of them will meet = 12:30 + 3:00 = 15:30 = 3:30 PM
IMO C
Asked: If Desmina’s Type 2 phaser would have taken 6 hours to reach Adriella’s original location, what time did the two of them meet?
Work done by Adriella till 12:30 = .5/7 = 1/14
Work left = 1 - 1/14 = 13/14
Work done by Adriella and Desmina in 1 hour = 1/6 + 1/7 = 13/42
Time taken by both to complete the work = 42/13 * 13/14 = 42/14 = 3 hours
The two of them will meet = 12:30 + 3:00 = 15:30 = 3:30 PM
IMO C
Thelegend2631
Posts: 371
06 Jun 2021, 09:50
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Take LCM as their Distance.
LCM ( 7,6 ) = 42
so Speeds of a and be will be 6,7
so by 12.30 a would have travelled 3 units.
now we need to know time for 42- 3 = 39 units when they are acting in opposite directions.
hence 39/(6+7 ) = 3
Hence, they will meet at 12.30 + 3 = 3.30 P.M. And have LUNCH Soon.
LCM ( 7,6 ) = 42
so Speeds of a and be will be 6,7
so by 12.30 a would have travelled 3 units.
now we need to know time for 42- 3 = 39 units when they are acting in opposite directions.
hence 39/(6+7 ) = 3
Hence, they will meet at 12.30 + 3 = 3.30 P.M. And have LUNCH Soon.
