Last visit was: 22 Apr 2026, 13:26 It is currently 22 Apr 2026, 13:26
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
junii
User avatar
Joined: 15 Sep 2018
Last visit: 20 May 2022
Posts: 151
Own Kudos:
145
 [17]
Given Kudos: 897
Location: Australia
Schools: Alberta University Sauder DeGroote Schulich Jan'22 Intake
GMAT 1: 620 Q48 V28
Schools: Alberta University Sauder DeGroote Schulich Jan'22 Intake
GMAT 1: 620 Q48 V28
Posts: 151
Kudos: 145
 [17]
In the given figure, ABC is right-angled triangle, right-angled at B. 04 Jul 2021, 02:26
Kudos
Add Kudos
17
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

75% (hard)

Question Stats:

58% (02:47) correct 42% (02:46) wrong based on 184 sessions

History

Date
Time
Result
Not Attempted Yet

In the given figure, ABC is right-angled triangle, right-angled at B. If angle BAC = 30° what is the y-coordinate of B?

A. \( 2\sqrt{}3\)
B. \( 4\sqrt{}3\)
C. \(2+2\sqrt{}3\)
D. \(4+\sqrt{}3\)
E. None of the above
​
Show Spoiler
Attachment:
geometry.PNG
geometry.PNG [ 17.64 KiB | Viewed 5304 times ]

ShowHide Answer
Official Answer
D
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 22 Apr 2026
Posts: 11,229
Own Kudos:
44,993
 [3]
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
My Reviews
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,229
Kudos: 44,993
 [3]
In the given figure, ABC is right-angled triangle, right-angled at B. 04 Jul 2021, 10:03
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
junii

In the given figure, ABC is right-angled triangle, right-angled at B. If angle BAC = 30° what is the y-coordinate of B?

A. \( 2\sqrt{}3\)
B. \( 4\sqrt{}3\)
C. \(2+2\sqrt{}3\)
D. \(4+\sqrt{}3\)
E. None of the above
​
Show Spoiler
Attachment:
The attachment geometry.PNG is no longer available

Show more


Draw a perpendicular from B that meets AC at D.

Two ways.

I. Visual
Line AC is 4 from x axis, so y-coordinates of B will be 4+length of AD.
Only D is in that format. In all probability, D should be the answer.

II. 30-60-90
ABC is 30-60-90 and AC is 7-3=4.
Thus, AB opposite \(60^o\) will be \(4*\sqrt{3}/2=2\sqrt{3}\)

Now ABD is also 30-60-90 so sides will be in ratio \(1:\sqrt{3:2}\).
Thus BD opposite \(30^o\) will be \(2\sqrt{3}/2=\sqrt{3}\)

Y-Coordinate of B = 4+\(\sqrt{3}\)


D
Attachments

82473241-936F-4FBB-A69D-1D8D16F7042F.jpeg
82473241-936F-4FBB-A69D-1D8D16F7042F.jpeg [ 32.6 KiB | Viewed 4955 times ]

User avatar
pandajee
User avatar
Joined: 27 Nov 2018
Last visit: 17 Dec 2022
Posts: 56
Own Kudos:
46
 [1]
Given Kudos: 70
Posts: 56
Kudos: 46
 [1]
In the given figure, ABC is right-angled triangle, right-angled at B. 04 Jul 2021, 13:14
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
chetan2u
junii

In the given figure, ABC is right-angled triangle, right-angled at B. If angle BAC = 30° what is the y-coordinate of B?

A. \( 2\sqrt{}3\)
B. \( 4\sqrt{}3\)
C. \(2+2\sqrt{}3\)
D. \(4+\sqrt{}3\)
E. None of the above
​
Show Spoiler
Attachment:
geometry.PNG



Draw a perpendicular from B that meets AC at D.

Two ways.

I. Visual
Line AC is 4 from x axis, so y-coordinates of B will be 4+length of AD.
Only D is in that format. In all probability, D should be the answer.

II. 30-60-90
ABC is 30-60-90 and AC is 7-3=4.
Thus, AB opposite \(60^o\) will be \(4*\sqrt{3}/2=2\sqrt{3}\)

Now ABD is also 30-60-90 so sides will be in ratio \(1:\sqrt{3:2}\).
Thus BD opposite \(30^o\) will be \(2\sqrt{3}/2=\sqrt{3}\)

Y-Coordinate of B = 4+\(\sqrt{3}\)


D
Show more

chetan2u
In the below statement of yours, i think u meant 4 + length of BD
"Line AC is 4 from x axis, so y-coordinates of B will be 4+length of AD."
Also, option B & C may not be in the format of "4 + something", but their values are more than 4.
Option B - 4 * sqrt(3) = 6.8
Option C - 2 + 2 sqrt(3) = 2 + 3.4 = 5.4

So, if we see at the values of option b & c, they also seem to be good candidate for answer. Request your comment.
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 22 Apr 2026
Posts: 11,229
Own Kudos:
44,993
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
My Reviews
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,229
Kudos: 44,993
In the given figure, ABC is right-angled triangle, right-angled at B. 04 Jul 2021, 19:47
Kudos
Add Kudos
Bookmarks
Bookmark this Post
pandajee
chetan2u
junii

In the given figure, ABC is right-angled triangle, right-angled at B. If angle BAC = 30° what is the y-coordinate of B?

A. \( 2\sqrt{}3\)
B. \( 4\sqrt{}3\)
C. \(2+2\sqrt{}3\)
D. \(4+\sqrt{}3\)
E. None of the above
​
Show Spoiler
Attachment:
geometry.PNG



Draw a perpendicular from B that meets AC at D.

Two ways.

I. Visual
Line AC is 4 from x axis, so y-coordinates of B will be 4+length of AD.
Only D is in that format. In all probability, D should be the answer.

II. 30-60-90
ABC is 30-60-90 and AC is 7-3=4.
Thus, AB opposite \(60^o\) will be \(4*\sqrt{3}/2=2\sqrt{3}\)

Now ABD is also 30-60-90 so sides will be in ratio \(1:\sqrt{3:2}\).
Thus BD opposite \(30^o\) will be \(2\sqrt{3}/2=\sqrt{3}\)

Y-Coordinate of B = 4+\(\sqrt{3}\)


D

chetan2u
In the below statement of yours, i think u meant 4 + length of BD
"Line AC is 4 from x axis, so y-coordinates of B will be 4+length of AD."
Also, option B & C may not be in the format of "4 + something", but their values are more than 4.
Option B - 4 * sqrt(3) = 6.8
Option C - 2 + 2 sqrt(3) = 2 + 3.4 = 5.4

So, if we see at the values of option b & c, they also seem to be good candidate for answer. Request your comment.
Show more

Hi, thanks. It is BD and a typo.

Now yes answer can be any of the B, C, D and E.

What would be BD in each case.
In B, 4+x=4\(\sqrt{3}……x=4(\sqrt{3}-1)\)
In C, x=\(2\sqrt{3}-2\)
And in D, \(x=\sqrt{3}\)

BD is opposite 30 degree angle. Which value of x fits in properly. It is \(\sqrt{3}\).
So, I meant that chances are high that it is D.
That was if you are in a hurry and do not have a clue on how to proceed.
But the proper method gives you the exact answer.
User avatar
crimson_noise
User avatar
Joined: 14 May 2024
Last visit: 21 Apr 2026
Posts: 57
Own Kudos:
21
Given Kudos: 14
GMAT Focus 1: 615 Q80 V85 DI77
GMAT Focus 1: 615 Q80 V85 DI77
Posts: 57
Kudos: 21
In the given figure, ABC is right-angled triangle, right-angled at B. 26 Feb 2026, 09:43
Kudos
Add Kudos
Bookmarks
Bookmark this Post
From the diagram we can find that ac= 4
Sin ø =1/2 = BC /ac = bc/4
So, bc=2
Draw a perpendicular from B to AC and name the point intersect as D.
Again, sin ø= 1/2 = BD/2✓3
So, bd= ✓3
Finally, distance of B from x-axis is bd+ 4 = 4 +✓ 3
User avatar
Budhaditya_Saha
User avatar
Joined: 01 Aug 2023
Last visit: 20 Apr 2026
Posts: 43
Own Kudos:
11
Given Kudos: 30
Posts: 43
Kudos: 11
In the given figure, ABC is right-angled triangle, right-angled at B. 10 Mar 2026, 10:13
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Is this relevant for GMAT focus edition?
junii

In the given figure, ABC is right-angled triangle, right-angled at B. If angle BAC = 30° what is the y-coordinate of B?

A. \( 2\sqrt{}3\)
B. \( 4\sqrt{}3\)
C. \(2+2\sqrt{}3\)
D. \(4+\sqrt{}3\)
E. None of the above

Show Spoiler
Attachment:
geometry.PNG

Show more
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,754
Own Kudos:
810,659
Given Kudos: 105,823
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,754
Kudos: 810,659
In the given figure, ABC is right-angled triangle, right-angled at B. 10 Mar 2026, 10:16
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Budhaditya_Saha
Is this relevant for GMAT focus edition?

Show more
___________________
No.
Moderators:
Bunuel
Math Expert
109754 posts
Krunaal
Tuck School Moderator
853 posts