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Area = 1/4 (pi)r^2 = 16 pi => r^2 = 64 => r = 8
Arc length = 1/4 (2pir) = 1/2 (8pi) = 4pi (B)
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Given,
Angle ABC = 90

Area of shaded region = θ/360 * pi * r^2
90/360 * pi * r^2 = 16 *pi
1/4 * pi * r^2 =16 *pi
r^2 = 64
r =8

Length of the arc = θ/360 * 2*pi*r = 1/4 * 2*pi*8 = 4 *pi

IMO B
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It is not explicitly mentioned that Angle ABC is 90degree
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kri1311
It is not explicitly mentioned that Angle ABC is 90degree

See that little square at B? That's an indication that B is a right angle.
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Yeah I see it. Usually in GMAT problems, I see that they mention it explicitly which wasn't the case here.
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Bunuel

If B is the center of the circle in the figure above and the area of the shaded region is 16π, what is the length of arc ADC?

A. 4
B. 4π
C. 16
D. 8π
E. 16π

IMO B, 0.20 min.

We know that the area of this quarter circle =\( 1/4*\pi * r^2\);

So we get r = 8;
Hence total perimeter is \(16 \pi\) , Length of ADC is \(4 \pi\)
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1) (90/360) times pi r^2 = 16n

2) Figure out what r is equal to algebraically

3) Plug it into the formula 2 pi r

4) Multiply the result by (90/360)
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kri1311
Yeah I see it. Usually in GMAT problems, I see that they mention it explicitly which wasn't the case here.

That is a commonly used notation in math and GMAT also uses it. For example, check the following GMAT Prep question: https://gmatclub.com/forum/in-the-figur ... 85154.html
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kri1311
Yeah I see it. Usually in GMAT problems, I see that they mention it explicitly which wasn't the case here.

What was your logic? It shows the right angle BUT you are going to ignore it since the question stem did not mention it?
You have to pay attention to the details on the GMAT and ask WHY rather than just sort of brush things aside and just do your thing. It is not a test of brute force but details.
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