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Bunuel
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GMAT 1: 760 Q51 V42
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Bunuel
Which of the following is NOT equal to the square of an integer?

A \(\sqrt{1}\)

B \(\frac{4^2}{2^2}\)

C 81

D 41 - 9

E 36

A is 1 squared.

B is \((\frac{4}{2})^2 = 2^2\)

C is 9 squared and E is 6 squared, only D = 32 which is not a square.

Ans: D
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For those confused by the \(\sqrt{1}\) and perfect squares. Don't overthink like I did - the \(\sqrt{1}\) = 1 and 1^2 is also 1. That leaves (D) as the only correct choice.
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Hello!

Let's go through these one by one


A. \(\sqrt{1}\) = 1

1 = \(1^2\) so A is out



B. \(\frac{4^2}{2^2}\) = \(\frac{16}{4}\) = 4

4 = \(2^2\), B is out



C. 81 = \(9^2\), out



D. 41 - 9 = 32

\(\\
\sqrt{32}\) is not an integer

\(\sqrt{25}\) = 5
\(\sqrt{36}\) = 6
\(\sqrt{32}\) = 5.something

(D) is the answer



E. Just for fun lets do E. Never enough math right?

36 = \(6^2\) E is out
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