If x, y, and z are consecutive odd integers where x

Question

If x, y, and z are consecutive odd integers where x < y < z and x + y + z < z, then which of the following could be the value of x ?

A. −3
B. −1
C. 0
D. 1
E. 3

Archit3110 · Answer

given that
x<y<z
and x + y + z < z
use plug in 
only option A suffices the given condition
x=-3 , y= -1 & z= 1
option A

darkphoenix · Answer

Option A.
the consecutive numbers should be of opposite sign to satisfy the conditions.

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ManifestDreamMBA · Answer

x + y + z < z 
 x + y < 0 
 y = x + 2 (consecutive odd) 
 x + x + 2 < 0 
 2x < -2 
 x<-1 
 x = -3 satisfies

sompant_98 · Answer

Since x, y, and z are consecutive odd integers, we can express them as:
 
 x = n 
 y = n + 2 
 z = n + 4  
where 'n' is an odd integer.

We are given that x + y + z < z. Substitute the expressions for x, y, and z:
n + (n + 2) + (n + 4) < n + 4

3n + 6 < n + 4
2n < -2
n < -1

We are looking for a possible value of x, which is equal to n. Since n must be an odd integer less than -1, let's look at the options:
 
 A. -3: -3 is an odd integer less than -1. This is a possible value for x. 
 B. -1: -1 is not less than -1. 
 C. 0: 0 is not an odd integer. 
 D. 1: 1 is not less than -1. 
 E. 3: 3 is not less than -1.

The only possible value for x is -3

If x, y, and z are consecutive odd integers where x < y < z and x + y

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