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23 Jul 2021, 20:20
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (02:20) correct
27%
(02:04)
wrong
based on 143
sessions
History
Date
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Not Attempted Yet
A and B live in the same house and work in the same place. A takes 20 minutes and B takes 30 minutes to reach workplace. B starts from the house 5 minutes earlier than A starts. How many minutes would A take to meet B?
(a) 25 minutes
(b) 30 minutes
(c) 10 minutes
(d) 5 minutes
(e) 35 minutes
(a) 25 minutes
(b) 30 minutes
(c) 10 minutes
(d) 5 minutes
(e) 35 minutes
globaldesi
Joined: 28 Jul 2016
Last visit: 23 Feb 2026
Posts: 1,141
Given Kudos: 67
Location: India
Concentration: Finance, Human Resources
Schools: ISB '18 (D)
GPA: 3.97
WE:Project Management (Finance: Investment Banking)
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23 Jul 2021, 21:27
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let the distance be d
so B's speed = \(\frac{d}{30}\)
distance covered in 5 mins = \(\frac{d}{30}*6 \)=\( \frac{d}{6}\)
time taken by A to cover tis distance and meet B
is \([m]\frac{d}{6} \)/\frac{ \([fraction]d}{20}\)-\(\frac{d}{30}\)[/fraction][/m]
= \(\frac{1}{6/ 1/60}\)
= 10 mins
C
so B's speed = \(\frac{d}{30}\)
distance covered in 5 mins = \(\frac{d}{30}*6 \)=\( \frac{d}{6}\)
time taken by A to cover tis distance and meet B
is \([m]\frac{d}{6} \)/\frac{ \([fraction]d}{20}\)-\(\frac{d}{30}\)[/fraction][/m]
= \(\frac{1}{6/ 1/60}\)
= 10 mins
C
23 Jul 2021, 21:50
Kudos
Bookmarks
speed of A : speed of B = 3:2 (because time taken A:B for same distance = 2:3 OR s=distance/time, that is d/30 & d/20 respectively, equals 2:3)
In t time, A will cover 3t and B with a headstart of 5 min (ie extra 5 mins) will cover 2(t+5). Distance covered by both is same.
So, 3t = 2(t+5)
t = 10 (Ans: C)
In t time, A will cover 3t and B with a headstart of 5 min (ie extra 5 mins) will cover 2(t+5). Distance covered by both is same.
So, 3t = 2(t+5)
t = 10 (Ans: C)
