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Case 1:- When x is negative

-(x-3) = 6
=> -x + 3 = 6
=> -x = 3
=> x = -3

Case 2:- When x is positive

x - 3 = 6
=> x = 9

Ans. {-3,9}
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If |x - 3| = 6, then either x - 3 = 6 or x - 3 = -6

=> Either x = 9 or x =-3 (option c)

Alternately, utilize the answer choices.

You can start with checking for 9 as its present in four of the options and if it is eliminated we can straight find the right answer.

At x=9,|9 - 3| = 6 and hence only E stands eliminated.
Similarly plug in -3 and eliminate A,B & D because it satisfies the modulus equation to reach to option c as the right answer.
If you plugged -9, eliminate B and then check for -3.

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As we have |x - 3| in the equation so we will have two cases
-
Case 1: x - 3 ≥ 0 => x ≥ 3
=> |x - 3| = x - 3
=> x - 3 = 6
=> x = 3 + 6 = 9

But condition was x ≥ 3 and 9 ≥ 3
=> x = 9 is a SOLUTION
-
Case 2: x - 3 ≤ 0 => x ≤ 3
=> |x - 3| = - (x - 3) = 3 - x
=> 3 - x = 6
=> x = 3 - 6 = -3

But condition was x ≤ 3 and -3 ≤ 3
=> x = -3 is a SOLUTION


So, Answer will be C
Hope it helps!

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