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| As we have |x - 3| in the equation so we will have two cases | |
| - Case 1: x - 3 ≥ 0 => x ≥ 3 => |x - 3| = x - 3 => x - 3 = 6 => x = 3 + 6 = 9 But condition was x ≥ 3 and 9 ≥ 3 => x = 9 is a SOLUTION | - Case 2: x - 3 ≤ 0 => x ≤ 3 => |x - 3| = - (x - 3) = 3 - x => 3 - x = 6 => x = 3 - 6 = -3 But condition was x ≤ 3 and -3 ≤ 3 => x = -3 is a SOLUTION |

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