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16 Aug 2021, 03:45
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
84% (02:48) correct
16%
(02:13)
wrong
based on 49
sessions
History
Date
Time
Result
Not Attempted Yet
The average weight of 3 men A, B and C is 84 Kg. Another man, D, joins the group, and the average weight becomes 80 Kg. If another man, E, whose weight is 3 Kg more than that of D, replaces A, then average weight of B, C, D and E becomes 79 Kg. The weight of A is:
(A) 70 Kg
(B) 72 Kg
(C) 75 Kg
(D) 80 Kg
(E) 81 Kg
(A) 70 Kg
(B) 72 Kg
(C) 75 Kg
(D) 80 Kg
(E) 81 Kg
16 Aug 2021, 04:00
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Age of D = 84-(4*4) = 68
Age of E = 68+3= 71
D + E = 139
Avg age of B,C,D,E = 79
Total age = 79*4 = 316
Sum of B & C = 316-139 = 177
Therefore, age of A = 84*3 - 177 = 75
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Age of E = 68+3= 71
D + E = 139
Avg age of B,C,D,E = 79
Total age = 79*4 = 316
Sum of B & C = 316-139 = 177
Therefore, age of A = 84*3 - 177 = 75
Posted from my mobile device
16 Aug 2021, 22:55
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A + B + C = 84 × 3 = 252.....................(1)
A + B + C + D = 80 × 4 = 320...............(2)
On solving equation (1) and (2)
D = 320 - 252= 68
E's weight = 68 + 3 = 71
B + C + D + E = 79 × 4 = 316
B + C + D + 71 = 316
B + C + D = 316 - 71 = 245
Now, from equation (2)
(A + B + C + D) - (B + C + D)
A = 320 - 245 = 75 kg
OA should be C
A + B + C + D = 80 × 4 = 320...............(2)
On solving equation (1) and (2)
D = 320 - 252= 68
E's weight = 68 + 3 = 71
B + C + D + E = 79 × 4 = 316
B + C + D + 71 = 316
B + C + D = 316 - 71 = 245
Now, from equation (2)
(A + B + C + D) - (B + C + D)
A = 320 - 245 = 75 kg
OA should be C
