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21 Sep 2021, 11:01
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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91% (01:11) correct
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kapil1995
Let these two sides be the smaller ones, so that we get largest possible triangle.
The area would be maximum when the triangle is a right angled triangle with sides other than hypotenuse as 12 and 24.
Area = \(\frac{1}{2}*12*24=144\)
A
21 Sep 2021, 11:55
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Asked: What will be maximum area of triangle with sides 12 and 24 ?
Maximum Area of triangle with sides = .5×12×24 = 144
IMO A
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Maximum Area of triangle with sides = .5×12×24 = 144
IMO A
Posted from my mobile device
21 Sep 2021, 20:26
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Considering 12 and 24 as 2 sides of the triangle, it is in x, 2x and root(3)x. So, the 3 sides are:
x=12 ----> base
2x= 24 ----> hypotenuse
root(3)x = 12*root(3) ----> height
Area of the triangle = 0.5 * base * height = 0.5 * 12 * 12*root(3) = 0.5*144* 1.73 = 124.56
which is not an option.
Please let me know where I am going wrong.
x=12 ----> base
2x= 24 ----> hypotenuse
root(3)x = 12*root(3) ----> height
Area of the triangle = 0.5 * base * height = 0.5 * 12 * 12*root(3) = 0.5*144* 1.73 = 124.56
which is not an option.
Please let me know where I am going wrong.
