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21 Mar 2022, 04:15
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
46% (02:18) correct
54%
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wrong
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A certain candy store sells jellybeans in the following six flavors only: banana, chocolate, grape, lemon, peach and strawberry. The jellybeans are sorted into boxes containing exactly 2, 3 or 4 different flavors, with each possible assortment of flavors appearing in exactly one box. What is the probability that any given box contains grape jellybeans?
A. \(\frac{1}{6}\)
B. \(\frac{1}{3}\)
C. \(\frac{2}{5}\)
D. \(\frac{1}{2}\)
E. \(\frac{3}{4}\)
Are You Up For the Challenge: 700 Level Questions
A. \(\frac{1}{6}\)
B. \(\frac{1}{3}\)
C. \(\frac{2}{5}\)
D. \(\frac{1}{2}\)
E. \(\frac{3}{4}\)
Are You Up For the Challenge: 700 Level Questions
21 Mar 2022, 06:42
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Probability of a grape in the 2 unit box:
Ways to pick 2
flavors=6!/2!4!= 15
Ways to pick 1 flavor from
5, since grape is assumed =
5
Probability: 5/15=1/3
Probability of grape in a 3 unit box:
Ways to pick 3 flavors=
6!/3!3! = 20
Ways to pick 2 flavors
from 5 = 5!/2!3!= 10
Probability: 10/20= 1/2
Probability of grape in 4 unit box:
Ways to pick 4 flavors=
6!/2!4!= 15
Ways to pick 3 flavors from
5= 5!/3!2!= 10
Probability= 10/15= 2/3
Assuming each assortment has an equal chance of being selected, 1/3, overall probability equals:
1/3*(1/3+1/2+2/3)=
1/3*3/2=
1/2
Posted from my mobile device
Ways to pick 2
flavors=6!/2!4!= 15
Ways to pick 1 flavor from
5, since grape is assumed =
5
Probability: 5/15=1/3
Probability of grape in a 3 unit box:
Ways to pick 3 flavors=
6!/3!3! = 20
Ways to pick 2 flavors
from 5 = 5!/2!3!= 10
Probability: 10/20= 1/2
Probability of grape in 4 unit box:
Ways to pick 4 flavors=
6!/2!4!= 15
Ways to pick 3 flavors from
5= 5!/3!2!= 10
Probability= 10/15= 2/3
Assuming each assortment has an equal chance of being selected, 1/3, overall probability equals:
1/3*(1/3+1/2+2/3)=
1/3*3/2=
1/2
Posted from my mobile device
TheGraceful
10 Sep 2022, 02:54
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