Bunuel
1 man, 3 women, and 4 boys can do a piece of work in 96 hours; 2men and 8 boys can do the same work in 80 hours, and 2 men and 3 women can do it in 120 hours. In how many hours can the same work be done by 5 men and 12 boys?
A. \(60\frac{3}{13}\) hours
B. \(40\) hours
C. \(43\frac{7}{11}\) hours
D. \(100\) hours
E. \(40\frac{7}{11}\) hours
Another method.
May seem long but is very quick if you grasp it.
The look at numbers should tell you to compare all of them.
1m+3w+4b can do the work in 96 hrs or 10 work 960 h but 2m+8b can do single work in 80h, meaning (2m+8b)/2 can do it in 2*80 or 160h.
Thus 1m+4b can do 6 work on their own in 6*160 hrs, so 3w do 10-6 or 4 works in 960h or 1 work in 240h.
1 woman can do the work in 3*240 or 720hNext 2m+3w can do one work in 120h or 2 work in 240h. But, 3w do one work in 240h, meaning the remaking work is done by 2m.
1 man can do the work in 2*240 or 480Finally 1m and 4b can do a work in 160h or 3 work in 3*160 or 480h while 1m can do it in 480h. Thus 4b do the remaining 2 work in 480h.
1 boy can do the work in 480*4/2 or 960h5m and 12 boys5m will do 5 work in 480h, while 12 boys can do 12 work in 960h or 6 work in 480h.
Thus, 5m and 12b can do 5+6 or 11 work in 480h.
Therefore, they can do one work in 480/11 hours.
C