Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
04 Jul 2022, 05:45
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (00:42) correct
9%
(01:47)
wrong
based on 44
sessions
History
Date
Time
Result
Not Attempted Yet
If the sum and difference of two numbers are 20 and 8 respectively, then the difference of their squares is:
(A) 12
(B) 28
(C) 80
(D) 160
(E) 180
(A) 12
(B) 28
(C) 80
(D) 160
(E) 180
04 Jul 2022, 06:12
Kudos
Bookmarks
Given a+b=20 and a-b=8
Since \(a^2-b^2\)=\((a-b) (a+b)\)
\(a^2-b^2\)= 20x8
\(a^2-b^2\)=160
Hence, D
Since \(a^2-b^2\)=\((a-b) (a+b)\)
\(a^2-b^2\)= 20x8
\(a^2-b^2\)=160
Hence, D
04 Jul 2022, 09:00
Kudos
Bookmarks
This question is simple but in the real test can be a bit scary due to the calculations.
Attachments
A5618FA2-E9DE-4488-B32C-08C42478240F.jpeg [ 232.25 KiB | Viewed 1292 times ]
