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06 Sep 2022, 17:55
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E
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If \(\frac{1}{2} +\frac{1}{3 }+\frac{1}{8} =\frac{23}{x}\), which of the following must be an integer?
I. \(\frac{x}{8}\)
II. \(\frac{x}{12}\)
III \(\frac{x}{24}\)
(A) I only
(B) II only
(C) I and III only
(D) II and III only
(E) I, II, and III
I. \(\frac{x}{8}\)
II. \(\frac{x}{12}\)
III \(\frac{x}{24}\)
(A) I only
(B) II only
(C) I and III only
(D) II and III only
(E) I, II, and III
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ChigataCOUL
06 Sep 2022, 18:04
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LCM \((2,3,8) = 8*3 = 24\)
\((\frac{1}{2})+(\frac{1}{3})+(\frac{1}{8}) = \frac{23}{x}\)
\((\frac{12}{24})+ (\frac{8}{24}) + (\frac{3}{24}) = \frac{23}{x}\)
\((\frac{23}{24}) = \frac{23}{x} => x= 24\)
24 is a multiple of 8,12, and 24.
Answer: E
\((\frac{1}{2})+(\frac{1}{3})+(\frac{1}{8}) = \frac{23}{x}\)
\((\frac{12}{24})+ (\frac{8}{24}) + (\frac{3}{24}) = \frac{23}{x}\)
\((\frac{23}{24}) = \frac{23}{x} => x= 24\)
24 is a multiple of 8,12, and 24.
Answer: E
06 Sep 2022, 23:30
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solve the given expression we get x = 24
so integer is possible for all given conditions
OPTION E
so integer is possible for all given conditions
OPTION E
carcass
