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19 Oct 2022, 02:44
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
63% (01:14) correct
37%
(01:25)
wrong
based on 827
sessions
History
Date
Time
Result
Not Attempted Yet
If k is an integer, the least possible value of |129 − 17k| is
A. 10
B. 9
C. 8
D. 7
E. 6
A. 10
B. 9
C. 8
D. 7
E. 6
19 Oct 2022, 06:33
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Bunuel
Solution:
- Hit and trial method. We have to plug different values of k and get 17k as close to 129 as possible
- If \(k=7\), then \(17k=17\times 7=119\) and \(|129-17k|=|129-119|=|10|=10\)
- But if \(k=8\), then \(17k=17\times 8=136\) and \(|129-17k|=|129-136|=|-7|=7\)
Hence the right answer is Option D
06 Nov 2022, 07:31
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Bunuel
The value of the modulus will be least when the term inside the modulus will be least.
Let's say 129 - 17k = 0
Then k = \(\frac{129}{17}\) = 7.XX
So we can just check for 7 and 8.
When
k = 7, |129-119| = 10
k = 8, |129-136| = 7
So, k = 8
Option D
