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I have a doubt:
S= (1,2,3,4,5,6,7,8,9,10,........,98,99)

For T, we will remove 3 and every 3rd integer afterwards from S.
=> T=(1,2,4,5,7,8,10,11,13,14,16,17,19,20,22,23,25,26,28,29,31.....97,98)

For V, we will remove 7 and 7th integer from T (and not S)
=> V= (1,2,4,5,8,10,11,13,14,16,19,20,22,23,25,26,29,31.....97,98)

Since we will remove 7th digit after 7 from T, both 23 and 29 would have to be part of set.
What am I getting wrong here?

Bunuel


Bunuel
Let S be the sequence of consecutive odd integers from 1 to 99. Sequence T is obtained from S by removing the integer 3 and then removing every 3rd integer after 3. Sequence V is obtained from T by removing the integer 7 and then removing every 7th integer after 7. Which of the following integers is in V?

A. 9
B. 15
C. 21
D. 23
E. 29
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vektr
I have a doubt:
S= (1,2,3,4,5,6,7,8,9,10,........,98,99)

For T, we will remove 3 and every 3rd integer afterwards from S.
=> T=(1,2,4,5,7,8,10,11,13,14,16,17,19,20,22,23,25,26,28,29,31.....97,98)

For V, we will remove 7 and 7th integer from T (and not S)
=> V= (1,2,4,5,8,10,11,13,14,16,19,20,22,23,25,26,29,31.....97,98)

Since we will remove 7th digit after 7 from T, both 23 and 29 would have to be part of set.
What am I getting wrong here?

Bunuel


Bunuel
Let S be the sequence of consecutive odd integers from 1 to 99. Sequence T is obtained from S by removing the integer 3 and then removing every 3rd integer after 3. Sequence V is obtained from T by removing the integer 7 and then removing every 7th integer after 7. Which of the following integers is in V?

A. 9
B. 15
C. 21
D. 23
E. 29

Check below:
Let S be the sequence of consecutive odd integers from 1 to 99
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Hi, could you kindly explain further why 29 is not the correct answer since we are removing the 7th integer after 7 which is 29 and not 23 to make up the set V or am I missing something here?
gmatophobia
As the number of terms is few, we can write the terms and check.

Set S = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 .. }

Sequence T is obtained from S by removing the integer 3 and then removing every 3rd integer after 3

Inference : Multiples of three from set S is removed (hence option A, B and C are not possible)

Set S = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 .. }

Sequence V is obtained from T by removing the integer 7 and then removing every 7th integer after 7

Remove 7 and then count 7 to the right in the remaining numbers.

29 gets removed & 23 remains.

Option D
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We are removing 7th digit after 7. So as 29 gets removed, we have 23 in the set.

The question asks, "which of these integers will be part of V".

Eipreel
Hi, could you kindly explain further why 29 is not the correct answer since we are removing the 7th integer after 7 which is 29 and not 23 to make up the set V or am I missing something here?
gmatophobia
As the number of terms is few, we can write the terms and check.

Set S = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 .. }

Sequence T is obtained from S by removing the integer 3 and then removing every 3rd integer after 3

Inference : Multiples of three from set S is removed (hence option A, B and C are not possible)

Set S = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 .. }

Sequence V is obtained from T by removing the integer 7 and then removing every 7th integer after 7

Remove 7 and then count 7 to the right in the remaining numbers.

29 gets removed & 23 remains.

Option D
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Well understood now thank you.
vektr
We are removing 7th digit after 7. So as 29 gets removed, we have 23 in the set.

The question asks, "which of these integers will be part of V".

Eipreel
Hi, could you kindly explain further why 29 is not the correct answer since we are removing the 7th integer after 7 which is 29 and not 23 to make up the set V or am I missing something here?
gmatophobia
As the number of terms is few, we can write the terms and check.

Set S = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 .. }

Sequence T is obtained from S by removing the integer 3 and then removing every 3rd integer after 3

Inference : Multiples of three from set S is removed (hence option A, B and C are not possible)

Set S = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 .. }

Sequence V is obtained from T by removing the integer 7 and then removing every 7th integer after 7

Remove 7 and then count 7 to the right in the remaining numbers.

29 gets removed & 23 remains.

Option D
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