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given
n=33*x+24
x = 0 ; n =24
x=1 ; n = 57
x=2 , n= 90
option E ; 3 is must be divisor of n

Bunuel
When the integer n is divided by 33, the remainder is 24. Which of the following must be a divisor of n?

A. 11
B. 9
C. 7
D. 4
E. 3

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Bunuel
When the integer n is divided by 33, the remainder is 24. Which of the following must be a divisor of n?

A. 11
B. 9
C. 7
D. 4
E. 3

n = { 24 , 57...........}

24 = 3*2^3
57 = 3*19

Thus, Divisior must be 3, Answer will be (E)
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Bunuel
When the integer n is divided by 33, the remainder is 24. Which of the following must be a divisor of n?

A. 11
B. 9
C. 7
D. 4
E. 3

[textarea]This is a PS Butler Question


We can set up the following equation:

n = 33Q + 24

n = 3(11Q + 8)

n/3 = 11Q + 8

Thus, n must be divisible by 3.

Answer: E
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