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hi,

could you please explain this part: "Net remainder = 122 - 2 = 120"?
I got -2 from the original expression but i'm not sure how you get 120 from that
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hi,

could you please explain this part: "Net remainder = 122 - 2 = 120"?
I got -2 from the original expression but i'm not sure how you get 120 from that

Hey meowmeowmeow22

Remainders can never be negative. So if you end up getting negative remainder the net (actual) remainder is equal to divisor + (the negative remainder)

Lets take an example to illustrate this

  • Divisor = 7
  • Dividend = 11

We know when 11 when divided by 7 results in a quotient of 1 and remainder of 4.

\(\frac{11}{7}\) can also be represented as \(\frac{14 - 3 }{ 7}\)

14/7 leaves a remainder = 0

-3/7 leaves a remainder = -3

As the remainder is negative, the actual remainder is 7 - 3 = 4

Similarly, in the above question we obtained a (negative) remainder of -2. Hence the actual remainder is 122 - 2 = 120

Hope this helps.
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↧↧↧ Detailed Video Solution to the Problem ↧↧↧


\(123^4 - 123^3 - 123^2 - 123\) = \(123^3(123 - 1) - 123( 123 + 1)\)
= \(123^3 * 122 - 123 * 124\)

Remainder of \(123^3 * 122 - 123 * 124\) by 122 = Remainder of \(123^3 * 122\) by 122 - Remainder of \(123 * 124\) by 122
= Remainder of 0 - Remainder of 123 by 122 * Remainder of 124 by 122 = 0 - 1*2 = 0 - 2= -2

Remainder of -2 by 122 will be same as -2 + 122 = 120

So, Answer will be D
Hope it helps!

Playlist on Solved Problems on Remainders here

Remainders by 2, 3, 5, 9, 10 and Binomial Theorem

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