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foragge1234
What is the greatest integer value of n such that \(9^n\) is a factor of 43! + 44!

A) 22

B) 18

C) 16

D) 10

E) 9


To find the max power of any num we need to see the prime factors of the number.

Here its 3, Max power is 10.

IMO D
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foragge1234
What is the greatest integer value of n such that \(9^n\) is a factor of 43! + 44!

A) 22

B) 18

C) 16

D) 10

E) 9

\(9^n = 3^{2n}\)

\(43! + 44! = 43! (1+44)\)

=\(43!45\)

There are two parts \(43! \) and \(45 \) we have to find the highest power of \(3\) in both the parts

In \(43!\) highest power of \(3 \)

\(\frac{43}{3} = 14\)

\(\frac{14}{3} = 4\)

\(\frac{4}{3} =1\)

\(14+4+1 = 19\) ...(I)

in \(45 \) hightest power of \(3\):

\(45 = 3*3*5 \) -> highest power of three is \( 2\) ...(II)

Thus highest power of three = \(19+ 2 = 21\)... (I)+(II)

But this has to be equated to \(2n\)

Hence \(2n=21 \)

\(n=10.5 \)

So highest power of \(3\) in \(3^{2n} = 10\)

Ans D

Hope it helped.
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Why can it not be solved like the following?

43! (45) / 9^n

43! will have 43/9 (4) ; 43/18 (2) ; 43/27 (1) ; 43/36 (1)
(Multiples of 9)

Adding: 4 + 0 + 2 + 1 + 1 + (1 from 45) = 9 ; what other 9 am i missing ; why is this approach incorrect ?
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skmaan
Why can it not be solved like the following?

43! (45) / 9^n

43! will have 43/9 (4) ; 43/18 (2) ; 43/27 (1) ; 43/36 (1)
(Multiples of 9)

Adding: 4 + 0 + 2 + 1 + 1 + (1 from 45) = 9 ; what other 9 am i missing ; why is this approach incorrect ?

For one, this method is used to find the power of a prime in a factorial; you cannot apply it to a non-prime. Also, for primes, we use the powers of the prime in the denominator, not the multiples.
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Is there a reason why we cannot solve it the following way? (FYI: Incorrect answer)

What is the greatest integer value of n such that 9^n is a factor translates to:
(43! + 44!)/(9^n)

Split it since the denominator is the same:

((43!)/(9^n)) + ((44!)/(9^n))

Calculate the number of 3's in each part.

43! = 19; Since it's 2n, n<=9
44! = 19; Since it's 2n, n<=9

Add 9 + 9 = 18. Yes, it's wrong, but I don't know why ...
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