Last visit was: 24 Apr 2026, 18:52 It is currently 24 Apr 2026, 18:52
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,818
Own Kudos:
Given Kudos: 105,873
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,818
Kudos: 811,087
 [23]
2
Kudos
Add Kudos
21
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,818
Own Kudos:
811,087
 [9]
Given Kudos: 105,873
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,818
Kudos: 811,087
 [9]
4
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
User avatar
gmatophobia
User avatar
Quant Chat Moderator
Joined: 22 Dec 2016
Last visit: 19 Apr 2026
Posts: 3,173
Own Kudos:
11,462
 [5]
Given Kudos: 1,862
Location: India
Concentration: Strategy, Leadership
Posts: 3,173
Kudos: 11,462
 [5]
1
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
General Discussion
User avatar
Maria240895chile
Joined: 23 Apr 2021
Last visit: 07 Jun 2023
Posts: 115
Own Kudos:
Given Kudos: 115
Posts: 115
Kudos: 59
Kudos
Add Kudos
Bookmarks
Bookmark this Post
could you please, explain this last part?

\(" = Remainder(\frac{30p}{7}+3)\)

Question: What is the remainder when the smallest possible integer value of n is divided by 7

Hence we need to minimize the remainder of\( \frac{30p}{7}\)
the minimum value of any remainder = 0

Minimum remainder = 3"

How you say that 3/7 is equal to 3, and that minimum reminder is 3?
User avatar
gmatophobia
User avatar
Quant Chat Moderator
Joined: 22 Dec 2016
Last visit: 19 Apr 2026
Posts: 3,173
Own Kudos:
11,462
 [1]
Given Kudos: 1,862
Location: India
Concentration: Strategy, Leadership
Posts: 3,173
Kudos: 11,462
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Maria240895chile
could you please, explain this last part?

\(" = Remainder(\frac{30p}{7}+3)\)

Question: What is the remainder when the smallest possible integer value of n is divided by 7

Hence we need to minimize the remainder of\( \frac{30p}{7}\)
the minimum value of any remainder = 0

Minimum remainder = 3"

How you say that 3/7 is equal to 3, and that minimum reminder is 3?

Maria240895chile
How you say that 3/7 is equal to 3

3 when divided by 7 leaves a remainder = 3

Quote:
that minimum reminder is 3

I am assuming you're referring to this part of the solution

Remainder(\(\frac{n}{7}\)) = Remainder(\(\frac{30p+3}{7}\))

= Remainder(\(\frac{30p}{7}\)) + Remainder(\(\frac{3}{7}\))

We can add remainders to get the net remainder.

In this case, Remainder(\(\frac{n}{7}\)) (read as Remainder when n is divided by 7) = Remainder(\(\frac{30p}{7}\)) + Remainder(\(\frac{3}{7}\))

Remainder(\(\frac{3}{7}\)) = 3

So we have have the expression as

Remainder(\(\frac{n}{7}\)) = some value + 3

The remainder will be least, when the term we are adding is least, i.e. when the term is 0.

Hence the minimum value = 3
User avatar
NehaKalani
Joined: 31 Mar 2022
Last visit: 05 Nov 2024
Posts: 18
Own Kudos:
9
 [1]
Given Kudos: 39
Posts: 18
Kudos: 9
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
When positive integer n is divided by 5, the remainder is 3, and when n is divided by 6, the remainder is 3. What is the remainder when the smallest possible integer value of n is divided by 7?

A. 0
B. 1
C. 2
D. 3
E. 4

Why is it wrong to think this way?

n = 5x+3 but also n = 6x+3
So n can be 8, 18, 23, 28, 33, 38, 43, 48 and so on...
But n also can be 9, 15, 21, 27, 33, 39 and so on...

The smallest value of n that satisfies both the conditions is 33.

And 33 when divided by 7 leaves a remainder of 5.

Bunuel, can you please explain why my approach is incorrect?
User avatar
Pasl
Joined: 01 Apr 2024
Last visit: 31 May 2024
Posts: 1
Given Kudos: 10
Location: Germany
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I thought 0 is not defined as "positive" integer... So in this turn, the least value would be 33...?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,818
Own Kudos:
Given Kudos: 105,873
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,818
Kudos: 811,087
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Pasl
I thought 0 is not defined as "positive" integer... So in this turn, the least value would be 33...?

Yes, 0 is neither positive nor negative integer but what does this has to do with the least value of n being 3?
User avatar
Ritze
Joined: 02 Aug 2025
Last visit: 25 Sep 2025
Posts: 2
Own Kudos:
Given Kudos: 8
Posts: 2
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Please show me a precise calculation where 3 divided by 7 gives a remainder of 3. Because i'm always arriving at the remainder of 2 and why 33 is not considered as the smallest value of n? do we have to factorize it or just pick the smallest single digit number in 33 which happens to be 3?

Bunuel
NehaKalani
When positive integer n is divided by 5, the remainder is 3, and when n is divided by 6, the remainder is 3. What is the remainder when the smallest possible integer value of n is divided by 7?

A. 0
B. 1
C. 2
D. 3
E. 4

Why is it wrong to think this way?

n = 5x+3 but also n = 6x+3
So n can be 8, 18, 23, 28, 33, 38, 43, 48 and so on...
But n also can be 9, 15, 21, 27, 33, 39 and so on...

The smallest value of n that satisfies both the conditions is 33.

And 33 when divided by 7 leaves a remainder of 5.

Bunuel, can you please explain why my approach is incorrect?

When positive integer n is divided by 5, the remainder is 3: n = 5q + 3. n can be 3, 8, 13, 18, 23, 28, 33, ...
When positive integer n is divided by 6, the remainder is 3: n = 6p + 3. n can be 3, 9, 15, 21, 27, 33, ...

As you can see the smallest possible value of n is 3, not 33. 3 divided by 7 gives the reminder of 3.

Notice that q and p are quotients and each of them can be 0.
User avatar
hr1212
User avatar
GMAT Forum Director
Joined: 18 Apr 2019
Last visit: 24 Apr 2026
Posts: 925
Own Kudos:
1,337
 [2]
Given Kudos: 2,217
GMAT Focus 1: 775 Q90 V85 DI90
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GMAT Focus 1: 775 Q90 V85 DI90
Posts: 925
Kudos: 1,337
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Build equations:

n = 5x + 3
n = 6y + 3

n = 7z + a?

When n is divided by both 5 and 6, remainder is 3. This occurs only when n is divided by 30 (5x6) and remainder is also 3 => n = 30p + 3

So numbers in this list can be derived by substituting values for p = 0,1,2,3,4,... which would result in 3, 33, 63, 93, 123,...

Smallest integer in this list is 3, which when divided by 7, would also give a remainder of 3

Ritze
Please show me a precise calculation where 3 divided by 7 gives a remainder of 3. Because i'm always arriving at the remainder of 2 and why 33 is not considered as the smallest value of n? do we have to factorize it or just pick the smallest single digit number in 33 which happens to be 3?

Bunuel
NehaKalani
When positive integer n is divided by 5, the remainder is 3, and when n is divided by 6, the remainder is 3. What is the remainder when the smallest possible integer value of n is divided by 7?

A. 0
B. 1
C. 2
D. 3
E. 4

Why is it wrong to think this way?

n = 5x+3 but also n = 6x+3
So n can be 8, 18, 23, 28, 33, 38, 43, 48 and so on...
But n also can be 9, 15, 21, 27, 33, 39 and so on...

The smallest value of n that satisfies both the conditions is 33.

And 33 when divided by 7 leaves a remainder of 5.

Bunuel, can you please explain why my approach is incorrect?

When positive integer n is divided by 5, the remainder is 3: n = 5q + 3. n can be 3, 8, 13, 18, 23, 28, 33, ...
When positive integer n is divided by 6, the remainder is 3: n = 6p + 3. n can be 3, 9, 15, 21, 27, 33, ...

As you can see the smallest possible value of n is 3, not 33. 3 divided by 7 gives the reminder of 3.

Notice that q and p are quotients and each of them can be 0.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,818
Own Kudos:
811,087
 [1]
Given Kudos: 105,873
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,818
Kudos: 811,087
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ritze
Please show me a precise calculation where 3 divided by 7 gives a remainder of 3. Because i'm always arriving at the remainder of 2 and why 33 is not considered as the smallest value of n? do we have to factorize it or just pick the smallest single digit number in 33 which happens to be 3?

Bunuel
NehaKalani
When positive integer n is divided by 5, the remainder is 3, and when n is divided by 6, the remainder is 3. What is the remainder when the smallest possible integer value of n is divided by 7?

A. 0
B. 1
C. 2
D. 3
E. 4

Why is it wrong to think this way?

n = 5x+3 but also n = 6x+3
So n can be 8, 18, 23, 28, 33, 38, 43, 48 and so on...
But n also can be 9, 15, 21, 27, 33, 39 and so on...

The smallest value of n that satisfies both the conditions is 33.

And 33 when divided by 7 leaves a remainder of 5.

Bunuel, can you please explain why my approach is incorrect?

When positive integer n is divided by 5, the remainder is 3: n = 5q + 3. n can be 3, 8, 13, 18, 23, 28, 33, ...
When positive integer n is divided by 6, the remainder is 3: n = 6p + 3. n can be 3, 9, 15, 21, 27, 33, ...

As you can see the smallest possible value of n is 3, not 33. 3 divided by 7 gives the reminder of 3.

Notice that q and p are quotients and each of them can be 0.

If you had 3 apples and wanted to distribute them evenly among 7 baskets, each basket would get 0 apples and 3 apples would be left over (remainder).

A remainder is the leftover quantity when a number is divided into equal parts. So when you divide 3 by 7, you are trying to split 3 into groups of 7. Since 7 is larger than 3, you cannot make even one full group, so you have 0 full groups and the leftover is 3. That leftover is the remainder.

When the divisor is larger than the dividend, the remainder is the same as the dividend. For example:

3 divided by 4 yields a remainder of 3: 3 = 4*0 + 3.
9 divided by 14 yields a remainder of 9: 9 = 14*0 + 9.
1 divided by 9 yields a remainder of 1: 1 = 9*0 + 1.

Remainders

Theory

Questions

For other subjects:

Hope it helps.
Moderators:
Math Expert
109818 posts
Tuck School Moderator
853 posts