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Bunuel
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Boys:girls = 3:1 or higher. So, overall average will be closer to the boys' average.
When 3:1 ratio, average= (0.25*(94-78)) +78 = 82.
If the ratio increases, the average may move below 82, which can be 80.

So, 80 & 82 ..option D
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I solved via weighted averages. I hope the approach is right.

We know that number of boys >=3 times number of girls. So we should get b/g >=3
1. For average as 84: b/g=[94-84]/[84-78] = 10/6 =1.67
2. For average as 82: b/g=[94-82]/[82-78] = 12/4 = 3
3. For average as 80: b/g=[94-80]/[80-78] = 14/2 = 7

So 82 and 80 should be possible.


Bunuel
There are at least three times as many boys as girls in a class. On a test, the boys’ average score is 78, and the girls’ average score is 94. Which of the following could be the average test score for the entire class?

I. 84
II. 82
III. 80

A. I only
B. II only
C. III only
D. II and III only
E. I, II, and III

700 level question

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