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11 Apr 2023, 01:30
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Difficulty:
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Question Stats:
75% (01:59) correct
25%
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Cylinder A, which has a radius of x and a height of y, has a greater surface area than does Cylinder B, which has a radius of y and a height of x. How much greater is the surface area of Cylinder A than that of Cylinder of B?
A. \(x^2 - y^2\)
B. \(2(x^2 - y^2)\)
C. \(\pi (x^2 - y^2)\)
D. \(2\pi (x^2 - y^2)\)
E. \(4\pi (x^2 - y^2)\)
A. \(x^2 - y^2\)
B. \(2(x^2 - y^2)\)
C. \(\pi (x^2 - y^2)\)
D. \(2\pi (x^2 - y^2)\)
E. \(4\pi (x^2 - y^2)\)
11 Apr 2023, 02:22
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Cylinder A, which has a radius of x and a height of y, has a greater surface area than does Cylinder B, which has a radius of y and a height of x. How much greater is the surface area of Cylinder A than that of Cylinder of B?
Surface area of cylinder = 2πr(r + h)
Surface area of Cylinder A = 2πx(x+y) = 2πx^2 + 2πxy
Surface area of cylinder B = 2πy(y+x) = 2πy^2 + 2πxy
SO difference is 2π(x^2 - y^2)
Answer D
Surface area of cylinder = 2πr(r + h)
Surface area of Cylinder A = 2πx(x+y) = 2πx^2 + 2πxy
Surface area of cylinder B = 2πy(y+x) = 2πy^2 + 2πxy
SO difference is 2π(x^2 - y^2)
Answer D
11 Apr 2023, 06:37
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Bunuel
The total surface area (T.S.A) of a cylinder with radius 'r' and height 'h' is given by
\(2*\pi*r(r + h)\)
T.S.A of Cylinder A = \(2*\pi*x(x + y)\)
T.S.A of Cylinder B = \(2*\pi*y(y + x)\)
Difference = \(2*\pi*x(x + y)\) - \(2*\pi*y(y + x)\)
= \(2*\pi*(x^2 + xy - y^2 - xy)\)
= \(2*\pi*(x^2 - y^2 )\)
Option D
