In a bus, there are 20 rows, and each row has 2 seats on either side

Question

In a bus, there are 20 rows, and each row has 2 seats on either side of the aisle. There are 2 emergency windows on each side of the bus at either end and each emergency window can be operated from exactly two window seats. If a person has opted for a window seat, then what is the probability that he will be assigned to a seat from which the emergency windows can be operated?

(A) \(\frac{1}{2}\)

(B) \(\frac{1}{4}\)

(C) \(\frac{1}{5}\)

(D) \(\frac{1}{10}\)

(E) \(\frac{2}{5}\)

(A)  \frac{1}{2}

(B)  \frac{1}{4}

(C)  \frac{1}{5}

(D)  \frac{1}{10}

(E)  \frac{2}{5}

gmatophobia · Answer

The bus has 20 rows, and each row has two window seats and two aisle seats. Total window seats in the bus = 20 * 2 = 40

Number of emergency windows = 2 on either sides = 2 * 2 = 4

Each emergency window can be operated from two window seats, hence the four emergency windows can be operated from 4 * 2 = 8 window seats.

Hence if a person is seated in any of these 8 seats, he/she can operate one of the emergency windows.

Required Probability =  \frac{8}{40}

=  \frac{1}{5}

Option C

RICHA1189 · Answer

If there are 20 seats on 1 side . Probability will be 4/20 = 1/5
Same as 8/40 (both the sides) = 1/5

Answer c 1/5

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In a bus, there are 20 rows, and each row has 2 seats on either side

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