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RenB
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A farmer decides to plant a row of trees along one side of a road. He 19 May 2023, 04:41
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Question Stats:

64% (01:15) correct 36% (01:17) wrong based on 582 sessions

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A farmer decides to plant a row of trees along one side of a road. He decides to plant one tree every 15 metres. If the road is 460 metres long what is the maximum number of trees the farmer could plant?
A. 28
B. 29
C. 30
D. 31
E. 32
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D
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gmatophobia
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A farmer decides to plant a row of trees along one side of a road. He 19 May 2023, 05:13
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RenB
A farmer decides to plant a row of trees along one side of a road. He decides to plant one tree every 15 metres. If the road is 460 metres long what is the maximum number of trees the farmer could plant?
A. 28
B. 29
C. 30
D. 31
E. 32
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As we need the maximum number of trees, we can start at the zeroth mark.

Therefore we can plant the first tree at the 0th mark, the second tree at the 15th mark, the third tree at the 30th mark, and so on.

A = {0, 15, 30, 45, 60 ... 450}

The numbers are in arithmetic progression with a common difference of 15.

\(450 = 0 + (n-1)15\)

\(n - 1 =\frac{ 450}{15} = 30\)

\(n = 31\)

Option D
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A farmer decides to plant a row of trees along one side of a road. He 02 Jun 2023, 00:52
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can't we just divide 460/5, also we have to account for the 0th position, can't we take 461?
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harjas2222
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A farmer decides to plant a row of trees along one side of a road. He 05 Jun 2025, 06:28
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a doubt, why take 460 as 450?

thank you
gmatophobia
RenB
A farmer decides to plant a row of trees along one side of a road. He decides to plant one tree every 15 metres. If the road is 460 metres long what is the maximum number of trees the farmer could plant?
A. 28
B. 29
C. 30
D. 31
E. 32

As we need the maximum number of trees, we can start at the zeroth mark.

Therefore we can plant the first tree at the 0th mark, the second tree at the 15th mark, the third tree at the 30th mark, and so on.

A = {0, 15, 30, 45, 60 ... 450}

The numbers are in arithmetic progression with a common difference of 15.

\(450 = 0 + (n-1)15\)

\(n - 1 =\frac{ 450}{15} = 30\)

\(n = 31\)

Option D
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GraemeGmatPanda
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A farmer decides to plant a row of trees along one side of a road. He 05 Jun 2025, 06:36
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Because the trees are planted every 15 metres, so we have to take the closest number to 460 that is divisible by 15 (and not above 460). That is 450

Hope this helps!
harjas2222
a doubt, why take 460 as 450?

thank you
gmatophobia
RenB
A farmer decides to plant a row of trees along one side of a road. He decides to plant one tree every 15 metres. If the road is 460 metres long what is the maximum number of trees the farmer could plant?
A. 28
B. 29
C. 30
D. 31
E. 32

As we need the maximum number of trees, we can start at the zeroth mark.

Therefore we can plant the first tree at the 0th mark, the second tree at the 15th mark, the third tree at the 30th mark, and so on.

A = {0, 15, 30, 45, 60 ... 450}

The numbers are in arithmetic progression with a common difference of 15.

\(450 = 0 + (n-1)15\)

\(n - 1 =\frac{ 450}{15} = 30\)

\(n = 31\)

Option D
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