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Given: Let n be a positive integer such that the number of positive factors of \(5^n\) is 15.
Asked: What is the number of positive factors of \(9^n\)?

Since the number of positive factors of \(5^n\) is 15.
n=14

Number of positive factors of \(9^n = 3^{2n} = 3^{28} = 29\)

IMO D
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why is n 14? 15 5's would be 5^15. Clearly I'm wrong but the three answers to these questions all just list the same info

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Let n be a positive integer such that the number of positive factors of \(5^n\) is 15. What is the number of positive factors of \(9^n\)?

A. 14
B. 15
C. 28
D. 29
E. 30


Number of positive factors of \(5^n\) is n+1 as ‘5’ is prime.
Thus, n+1=15 or n=14

Get \(9^n\) in prime factorisation => \(9^n=3^{2n}\)
Thus, number of positive factors = (2n+1) = 2*14+1 =29
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The question says that the number of factors of \(5^{n}\) is 15 and not the number of 5’s

To calculate number of factors of any integer,

First make prime factorization of an integer \(k = a^{p} * b^{q} * c^{r}\), where a, b, and c are prime factors of k and p, q, and r are their powers.

The number of factors of k will be expressed by the formula (p+1)(q+1)(r+1).

Example: Finding the number of all factors of 450: \(2^{1} 3^{2} 5^{2}\)

Total number of factors of 450 including 1 and 450 itself is (1+1) * (2+1) * (2+1) = 18 factors.

In the given question k = \(5^{n}\) => we see 5 is already a prime number, for k to have 15 factors, n should be 14.

Mgerman42
why is n 14? 15 5's would be 5^15. Clearly I'm wrong but the three answers to these questions all just list the same info

chetan2u
mastergrinder
Let n be a positive integer such that the number of positive factors of \(5^n\) is 15. What is the number of positive factors of \(9^n\)?

A. 14
B. 15
C. 28
D. 29
E. 30


Number of positive factors of \(5^n\) is n+1 as ‘5’ is prime.
Thus, n+1=15 or n=14

Get \(9^n\) in prime factorisation => \(9^n=3^{2n}\)
Thus, number of positive factors = (2n+1) = 2*14+1 =29
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Your thinking: "15 factors means 5^15"
This mixes up the number of factors with the exponent.

When you have 5^n, the factors are:
5^0, 5^1, 5^2, 5^3, ... , 5^n

Notice we start from 5^0 = 1 (yes, 1 is always a factor!)

So if n = 14, the factors are:
5^0, 5^1, 5^2, 5^3, ... , 5^14

Count them: that's positions 0 through 14, which gives us 15 factors.

Formula: Number of factors of p^k = k + 1

The "+1" comes from including p^0 = 1 as a factor.
Mgerman42
why is n 14? 15 5's would be 5^15. Clearly I'm wrong but the three answers to these questions all just list the same info


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